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  • | <span class="aops-font">V</span> | V
    6 KB (924 words) - 21:31, 22 February 2024
  • For starters, we identify d as distance and v as velocity (speed) ...equation gives us: <math>\frac{d}{v}=\frac{1}{3}</math> and <math>\frac{d}{v+18}=\frac{1}{5}</math>.
    4 KB (608 words) - 17:05, 17 January 2024
  • ...e, we can set up a proportion based on the principle that <math>d=\frac{m}{V}</math>, thus <math>dV=m</math>.
    2 KB (325 words) - 14:21, 19 January 2021
  • 231. Gmaas once demanded Epic Games to give him 5,000,000 V-bucks for his 569823rd birthday. EDIT: This is why Gmaas no longer has an E
    69 KB (11,805 words) - 20:49, 18 December 2019
  • pair V = incenter(A,C,P); dot("$I_C$", V, NW);
    5 KB (1,004 words) - 15:15, 28 June 2020
  • <math>V</math> is the foot ot perpendicular from <math>O</math> to <math>AI_A.</mat
    6 KB (998 words) - 21:36, 17 October 2022
  • ...</math> to <math>A, B</math> and <math>C</math>, respectively, be <math>u, v</math> and <math>w</math>. ...est distance that <math>P</math> can be from <math>D</math> if <math>u^2 + v^2 = w^2</math>?
    1 KB (255 words) - 01:11, 20 February 2019
  • ...<math>\overline{MS}</math> intersects <math>\overline{OP}</math> at <math>V</math> . If <math>AB = 2,</math> <math>BC = 2005,</math> <math>CD = 4,</mat
    7 KB (1,094 words) - 15:39, 24 March 2019
  • r, s, t, u, v, w, x, y, and z such that n + l + v − y = 0
    14 KB (2,904 words) - 18:24, 16 May 2017
  • The vertices <math>V</math> of a centrally symmetric hexagon in the complex plane are given by <cmath>V=\left\{ \sqrt{2}i,-\sqrt{2}i, \frac{1}{\sqrt{8}}(1+i),\frac{1}{\sqrt{8}}(
    18 KB (2,878 words) - 01:47, 16 December 2023
  • ...th>1\leq j\leq 12</math>, an element <math>z_j</math> is chosen from <math>V</math> at random, independently of the other choices. Let <math>P={\prod}_{
    15 KB (2,418 words) - 16:58, 7 November 2022
  • <cmath>V = Bh/3</cmath> <cmath>V = (192)(25\sqrt{3}/2)/3</cmath>
    7 KB (1,177 words) - 15:55, 5 January 2024
  • <cmath>z \equiv 16 + 0 + v + 0 + w + 0 = 16 + v + w \pmod{32}, </cmath> where <math>v</math> represents <math>15\cdot 2^{2+2k}p^3</math> and <math>w</math> repre
    10 KB (1,657 words) - 19:08, 24 April 2023
  • ...ition offered at Walton High School (Walton MathFest was a high school (JV/V) level math tournament until the 2017-2018 school year).
    1 KB (158 words) - 20:16, 9 August 2017
  • ...ition offered at Walton High School (Walton MathFest was a high school (JV/V) level math tournament until the 2017-2018 school year).
    1 KB (158 words) - 20:20, 9 August 2017
  • One could also construct a graph G=(V,E) with the set V of vertices (also called nodes or points) and the set E of edges (also call
    5 KB (858 words) - 00:36, 29 November 2023
  • <math>\quad\bullet\qquad</math> <math>V,</math> a reflection across the <math>y</math>-axis. ...beled vertices back to their original positions? (For example, <math>R, R, V, H</math> is one sequence of <math>4</math> transformations that will send
    16 KB (2,417 words) - 01:03, 28 April 2022
  • <cmath>\bar V = \frac {3a^3}{\pi r^2 h} = \frac {3r}{\pi h} \cdot \left( \frac {a}{r} \ri <cmath> \bar V = \frac {3}{\pi f^3} \le \frac {8}{9 \pi} = 0.283.</cmath>
    6 KB (1,034 words) - 10:12, 7 June 2023
  • path h = ellipse((0.5,0),0.45,0.015), v = ellipse((0,0.5),0.015,0.45); filldraw(shift((j,i))*v,black);
    15 KB (2,237 words) - 23:08, 15 November 2023
  • ...>. Using the formula for the volume of a triangular pyramid, we have <math>V = \frac{1}{3} \cdot \frac{1}{2} \cdot 3 = \frac{1}{2}</math>. Also, since t Plugging <math>x</math> and <math>y</math> into the formula <math>V = \dfrac{b \cdot h}{3},</math> we find that the volume is <math>\boxed{2}</
    8 KB (1,286 words) - 13:29, 21 April 2024
  • path h = ellipse((0.5,0),0.45,0.015), v = ellipse((0,0.5),0.015,0.45); filldraw(shift((j,i))*v,black);
    4 KB (609 words) - 19:49, 27 August 2023
  • Now all these nine polyhedrons lie inside <math>2 P_1</math>. Let <math>V</math> be the volume of <math>P_1</math>.
    1 KB (242 words) - 13:55, 29 January 2021
  • The volume <math>V = \pi R^2H</math> is to be increased by the same fixed positive amount when
    1 KB (245 words) - 19:07, 17 May 2018
  • https://www.youtube.com/watch?v=sT-wxV2rYqs ...AC = b, AB = c, x_1 = BX, x_2 = CX, \frac{c+t}{x_1} = u, \frac{b+t}{x_2} = v.</math>
    13 KB (2,200 words) - 21:36, 6 January 2024
  • ..., we can always choose <math>3-r</math> as the remainder for our set <math>V</math>, giving us a total of <math>r + 3 - r \equiv 0 \pmod{3}</math>. The
    26 KB (4,044 words) - 13:58, 24 January 2024
  • <cmath>v_{13}(27^m-1^m)=v_{13}(26)+v(m)=1+v(m), 3m = n</cmath> which clearly implies <math>m=13</math> and <math>39 | n
    10 KB (1,448 words) - 06:30, 21 April 2024
  • ...<math>1800-x</math>. Since Eve is the slowest, we can call her speed <math>v</math>, so that Ina's speed is <math>2v</math> and Paul's speed is <math>4v ...e of <math>1800-x</math> which takes them a time of <math>\frac{1800-x}{4v+v}</math>. Paul must run the same distance back to <math>B</math>, so his tot
    3 KB (516 words) - 03:25, 16 January 2023
  • ...ots, v_n), \vec{w} = (w_1, \cdots, w_n)</math> is defined to be <math>\vec{v}\cdot\vec{w} = \sum_{i=1}^n v_i w_i</math>. The dot product is [[linear|bil ...el, from which the identity <math>\vec{v} \cdot \vec{v} = \left \Vert \vec{v} \right \Vert ^2</math> follows.
    1 KB (199 words) - 23:10, 19 February 2022
  • ...B travels half the time at <math>u</math> miles per hour and half at <math>v</math> miles per hour. The average speed of Car A is <math>x</math> miles p <cmath>y = \frac{u+v}{2}</cmath>
    2 KB (396 words) - 19:03, 22 June 2021
  • Let the volume of the trough be <math>V</math> liters. Also, let the rate of the cold water tap be <math>C</math> <cmath>V = 21E</cmath>
    1 KB (268 words) - 16:32, 28 July 2018
  • Of the following five statements, I to V, about the binary operation of averaging (arithmetic mean), <math>\text{V. Averaging has an identity element }</math>
    2 KB (432 words) - 13:57, 20 February 2020
  • ...positions of the midpoints <math> U</math> of <math> BA</math> and <math> V</math> of <math> AC</math> as <math> \angle OPA</math> varies?
    3 KB (499 words) - 13:29, 2 August 2021
  • <math>\quad\bullet\qquad</math> <math>V,</math> a reflection across the <math>y</math>-axis. ...beled vertices back to their original positions? (For example, <math>R, R, V, H</math> is one sequence of <math>4</math> transformations that will send
    16 KB (2,497 words) - 21:14, 12 November 2023
  • ...P}\setminus\{\mathbf{v}\}</math> obtained by omitting vector <math>\mathbf{v}</math> from <math>\mathcal{P}</math> can be partitioned into two sets of e
    2 KB (369 words) - 23:35, 21 April 2019
  • ...P}\setminus\{\mathbf{v}\}</math> obtained by omitting vector <math>\mathbf{v}</math> from <math>\mathcal{P}</math> can be partitioned into two sets of e
    531 bytes (88 words) - 23:37, 21 April 2019
  • ...egree of <math>V</math> (i.e. the number of edges coming into/out of <math>V</math>). This is because to visit any of these vertices, we would have to e ...isit each vertex <math>M(V)</math> times, and must traverse <math>2\cdot M(V)</math> edges connected to each vertex. Specifically, we must traverse all
    8 KB (1,306 words) - 22:18, 1 February 2020
  • 'v'
    19 KB (2,942 words) - 21:22, 21 January 2024
  • Let <math>P(3)=u</math> and <math>P(4) = v</math>. Substituting <math>x=3</math> and <math>x=4</math> into the above q u &= (3-u)(3-v) = 9 - 3u - 3v + uv\\
    10 KB (1,819 words) - 19:34, 17 September 2023
  • ...ngineer Panagiotis Verdes figured out how to make 6×6 and 7×7 cubes. The V-Cube 6 (a 6x6x6 Rubik’s cube) has 157 152 858 401 024 063 281 013 959 519 The 7x7x7 Rubik’s cube (the V-Cube 7) has 19 500 551 183 731 307 835 329 126 754 019 748 794 904 992 692
    5 KB (518 words) - 16:53, 19 February 2024
  • <math>\delta x'(t)=v(t)</math> <math>v'(t)=a(t)</math>
    3 KB (423 words) - 12:58, 8 July 2019
  • ...he base's area, and h is the height's length; for a pyramid, we have <math>V=\frac{1}{3}Bh</math>.
    1 KB (207 words) - 01:39, 15 January 2020
  • 231. Almighty Gmaas once demanded Epic Games to give him 5,000,000 V-bucks for his 569823rd birthday. EDIT: This is why Almighty Gmaas no longer
    85 KB (13,954 words) - 17:25, 22 March 2024
  • label("V", (2, 6), NE); label("V", (2, 6), NE);
    11 KB (1,707 words) - 17:10, 1 April 2024
  • <math>\quad\bullet\qquad</math> <math>V,</math> a reflection across the <math>y</math>-axis. ...beled vertices back to their original positions? (For example, <math>R, R, V, H</math> is one sequence of <math>4</math> transformations that will send
    10 KB (1,653 words) - 23:33, 3 August 2023
  • ...of a cone is <math>\frac{1}{3}\pi r^{2}h</math>. Plugging in we find <math>V = 3\pi \sqrt{7} \implies \boxed{\textbf{(C)}}</math>
    3 KB (493 words) - 16:14, 11 September 2023
  • ...the origin and select a point on each line to define vectors <math>\mathbf{v}_{i}=(x_{i},y_{i})</math>. <cmath>\mathbf{v}_1\cdot\mathbf{v}_2 = v_{1}v_{2}\cos\theta \quad\mathrm{and}\quad
    5 KB (895 words) - 15:03, 8 June 2023
  • <li><math>\log_b{(uv)}=\log_b u + \log_b v.</math></li><p>
    5 KB (680 words) - 16:40, 22 April 2024
  • Let <math>V</math> and <math>F</math> be the vertex and focus of the Parabola <math>P(x
    8 KB (1,223 words) - 15:02, 27 November 2022
  • ...an upright V.}\\ \textbf{(D)}\ \text{Two line segments forming an inverted V.}\\ \textbf{(E)}\ \text{None of these.}</math>
    1 KB (193 words) - 10:42, 6 July 2020
  • ...d a horizontal circle of radius <math>r</math> with a constant speed <math>v</math>, in a conical pendulum. The center of the circle is vertically below ...ath>16 kg</math> which slides at a speed of <math>v</math>, with <math>u > v</math>. Block A slides east while Block B slides in west. The surface has c
    2 KB (439 words) - 11:52, 1 August 2020
  • ...th>x=PT</math>, where the length <math>O_{1}O_{2}</math> splits as <math>u+v</math>. Because the lines <math>PQ</math> and <math>O_{1}O_{2}</math> are p ...u^{2}+(r+x)^{2}-u(r+x) \\ \triangle O_{1}OT&:(r+R_{1})^{2}=v^{2}+(r+x)^{2}+v(r+x)\end{align*}</cmath>
    17 KB (2,852 words) - 03:59, 7 February 2024
  • Lucky Seven V ARE YOU XPERIENCED? V
    3 KB (452 words) - 10:21, 17 November 2022
  • Suppose that on a parabola with vertex <math>V</math> and a focus <math>F</math> there exists a point <math>A</math> such
    15 KB (2,383 words) - 09:49, 25 June 2023
  • Denote <math>u = 1 - x</math>, <math>v = 1 - y</math>, <math>w = 1 - z</math>. \sqrt{(1-u)(1+v)} + \sqrt{(1+u)(1-v)} & = 1 \hspace{1cm} (1) \\
    15 KB (2,208 words) - 01:25, 1 February 2024
  • ...t{10}} , \sqrt{10} \right)</math>, <math>Q = \left( \sqrt{10} , \frac{10 - v}{\sqrt{10}} \right)</math>. We have <math>m_{HP} = \frac{3}{6 - u}</math> and <math>m_{PQ} = - \frac{v}{u}</math>.
    16 KB (2,274 words) - 09:02, 10 December 2022
  • Let <math>O</math> be the center of the base, <math>V</math> be the vertex of the base.
    8 KB (1,314 words) - 03:54, 5 July 2022
  • pair A, B, C, D, E, F, G, H, A1, B1, C1, D1, E1, F1, G1, H1, V; V = (3,0);
    24 KB (3,567 words) - 18:14, 30 August 2022
  • Now here comes the smart part. Substitute <math>y = \sqrt[3]{u} - \sqrt[3]{v}</math>. ...<math>u - 3\sqrt[3]{u^2v} + 3\sqrt[3]{uv^2} - v + p\sqrt[3]{u} - p\sqrt[3]{v} + q = 0</math>. Simplification:
    6 KB (1,059 words) - 14:42, 11 December 2020
  • Let <math>u = 10 – y, v = 9 – x.</math> https://www.youtube.com/watch?v=jDP2PErthkg
    5 KB (794 words) - 15:36, 30 August 2022
  • ...3}</math> then we can find a line <math>\ell</math> perpendicular to <math>v</math> such that <math>\ell</math> separates <math>S</math>, and any point Suppose there is no such direction <math>v</math>, then <math>S</math> is contained in a box with side length <math>n^
    3 KB (574 words) - 11:30, 14 May 2021
  • Suppose that on a parabola with vertex <math>V</math> and a focus <math>F</math> there exists a point <math>A</math> such ...d <math>Y</math> be the orthogonal projections of <math>F</math> and <math>V</math> onto <math>AQ</math>. Because <math>AF < AV</math>, there are two po
    4 KB (796 words) - 17:33, 13 July 2021
  • ...ur squares on the middle of the edges after n moves, and <math>V_n</math> (V for vertex) be the probability that Frieda is on a corner after n moves. Th https://youtube.com/watch?v=kHLR57iP0cU
    17 KB (2,801 words) - 07:29, 4 November 2022
  • ...<math>u</math> and <math>v</math> in <math>G</math>. Every tree on <math>|V|=n</math> vertices has exactly <math>n-1</math> edges.
    401 bytes (75 words) - 16:51, 2 November 2020
  • V&=\frac16\cdot AB\cdot AD\cdot BD \\
    3 KB (496 words) - 19:12, 28 October 2022
  • ...tuy + vy^2 + svy + tv</math>, simplifying to <math>y^4 + (s + u)y^3 + (t + v + su)y^2 + (sv + tu)y + tv</math>. [[Equating coefficients]] gives the foll ...begin{cases} s + u = 0 \text{ since the } y^3 \text{ term is 0} \\ p = t + v + su \\ q = sv + tu \\ r = tv \end{cases}</math>
    13 KB (2,376 words) - 16:56, 19 February 2024
  • ...</math> and <math>2</math> along <math>\textbf{u}</math> and <math>\textbf{v}</math> respectively, then find <cmath>\sum_{i=1}^{n}\|\textbf{r}_i\|^2.</c
    7 KB (1,149 words) - 17:16, 15 December 2020
  • ...đến sâu răng, mất răng. Vì vậy, cần phát hiện kịp thời và điều trị đúng cách mòn cổ răng. ...rãnh này, lâu dần tạo mảng bám, gây viêm nhiễm, tụt lợi và ảnh hưởng tới thẩm mỹ. Cổ răng mòn nhiều thậm chí có
    5 KB (1,261 words) - 05:15, 7 January 2021
  • ...math> OV</math> (but not in <math> \vec{OV}</math>) for some vertex <math> V</math> of the polygon. Each two of these lines are obtained one from anothe
    2 KB (284 words) - 11:02, 30 January 2021
  • label("V",(1.5,.3),N); ...>\text{(A)}\ \text{Z} \qquad \text{(B)}\ \text{U} \qquad \text{(C)}\ \text{V} \qquad \text{(D)}\ \ \text{W} \qquad \text{(E)}\ \text{Y}</math>
    1,023 bytes (167 words) - 15:57, 4 July 2023
  • If <math>V = gt + V_0</math> and <math>S = \frac {1}{2}gt^2 + V_0t</math>, then <math> <math> \textbf{(A)}\ \frac{2S}{V+V_0}\qquad
    737 bytes (129 words) - 22:53, 12 February 2021
  • ...$c$", D--C, N); label("$d$",D--A,W); label("$u$",D--B,2*dir(170)); label("$v$",A--C,S); ...c, d</math>, be the sides, <math>s</math> the semiperimeter, and <math>u, v</math>, the diagonals. Then the area, <math>K</math>, is given by <cmath>K
    10 KB (1,669 words) - 17:33, 12 January 2024
  • Denote <math>D' – A' = 2\vec V.</math> ...\triangle A'C'E'</math> into <math>\triangle D'F'B'</math> is <math>2\vec {V.}</math>
    5 KB (875 words) - 00:26, 23 May 2023
  • ...<math>n=2k+1</math>, just take <math>(u,v)= (k+1,k)</math> which <math>u^2-v^2=n</math>. Thus the only answer is <math>\boxed{f\equiv 1}</math> and we a https://www.youtube.com/watch?v=Q1NUBUYvOJc
    8 KB (1,492 words) - 00:23, 24 February 2024
  • ...th>t</math> is square free and <math>gcd(u,v,w) = 1</math>, find <math>t+u+v+w</math> if <math>x=\cos 20^o</math> and <math>y=\sin 20^o</math>.
    8 KB (1,385 words) - 12:55, 23 June 2021
  • We could assume a variable <math>v</math> which equals to both <math>\log_{20x} (22x)</math> and <math>\log_{2 So that <math>(20x)^v=22x \textcircled{1}</math>
    5 KB (778 words) - 18:14, 30 January 2024
  • ...s, plus the outer region, <math>E</math> is the number of edges, and <math>V</math> is the number of vertices. Temporarily disregarding the intersection <math>V=V_{i}+210=222</math>
    12 KB (2,025 words) - 14:56, 25 January 2024
  • ...\qquad \text{(iii) }x+y\ge a\\ \\ \qquad \text{(iv) }x+a\ge y\qquad \text{(v) }y+a\ge x</math>
    665 bytes (119 words) - 18:31, 28 August 2023
  • ...t,st),E); label("M",(cu,su),N);label("P",(cu,st),S); label("C",(cos(v),sin(v)),W); //Credit to Zimbalono for the diagram </asy>
    864 bytes (169 words) - 16:47, 23 June 2021
  • ...th>C(1) = 0</math> and our recursive rules for <math>C(n)</math> and <math>V(n)</math> as follows: n & V(n) & C(n) \\ \hline
    8 KB (1,309 words) - 00:31, 6 January 2023
  • .../math> bisects the angle between <math>\mathbf{u}</math> and <math>\mathbf{v}</math>.
    16 KB (2,526 words) - 00:53, 6 May 2023
  • ...h>. Hence, <math>B = \left( - 1 , u \right)</math>, <math>D = \left( 0 , - v \right)</math>. The slope of <math>AD</math> is <math>m_{AD} = \frac{v}{3}</math>.
    5 KB (756 words) - 03:40, 23 January 2023
  • v v
    2 KB (265 words) - 22:25, 15 April 2024
  • Let <math>G</math> be a graph with the set of vertices <math>V=\{v_1,v_2,v_3,\ldots, v_n\}</math>. We define its adjacency matrix <math>\
    1 KB (264 words) - 11:26, 3 March 2022
  • ...> the formula for variance if <math>X</math> is a [[population]] is <cmath>V = \frac{1}{n}\sum_{i=1}^n (x_i - \overline{x})^2.</cmath> Additionally, <math>V = \sigma^2</math> where <math>\sigma</math> is the population [[standard de
    749 bytes (122 words) - 19:16, 3 March 2022
  • ...>, (2) <math>\hat{x}\equiv x\pmod{p^{n-k}}</math> and (3) <math>k=v(p'(x))=v(p'(\hat{x}))</math>. <center><cmath>v=u+p^{n-2k}zs\in u+p\mathbb{Z}_p\subset \mathbb{Z}_p^{\times}</cmath></cente
    13 KB (2,298 words) - 23:34, 28 May 2023
  • pair o = (0, 0), u = (1, 0), v = 0.8*dir(40), w = dir(70); draw(o--u--(u+v));
    7 KB (1,154 words) - 12:54, 20 February 2024
  • ...t{R}(\text{T}))</math> where <math>\text{R}(\text{T})=\{\text{T}(x)~|~x\in V\}</math>. In other words, rank is the dimension of the linear transformati ...aim that if <math>\beta=\{v_1,v_2,\ldots, v_n\}</math> is a basis of <math>V</math>, then
    5 KB (893 words) - 22:41, 28 May 2022
  • ...math> In accordance with Claim, <math>\angle BVD = \angle HVE \implies B', V,</math> and <math>B</math> are collinear.
    10 KB (1,751 words) - 15:34, 25 November 2022
  • ...mathbf{n}\,dS,</cmath> where <math>R</math> is a region whose volume <math>V(R)</math> shrinks to <math>0</math> about the point <math>p</math>, <math>\ ...mathbf{n}\,dS,</cmath> where <math>R</math> is a region whose volume <math>V(R)</math> shrinks to <math>0</math> about the point <math>p</math>, <math>\
    7 KB (1,189 words) - 06:00, 21 December 2022
  • ...the three roots of the polynomial. The lengthened prism's volume is <cmath>V = (a+2)(b+2)(c+2) = abc+2ac+2ab+2bc+4a+4b+4c+8 = abc + 2(ab+ac+bc) + 4(a+b+ We can substitute these into the expression, obtaining <cmath>V = \frac{6}{10} + 2\left(\frac{29}{10}\right) + 4\left(\frac{39}{10}\right)
    7 KB (1,111 words) - 21:00, 21 February 2024
  • ...e R.H.S. is a not a perfect square. Thus, the number of positive <math>(u, v)</math> is equal to the number of positive divisors of <math>2 r^2</math>. ...n if <math>(a, b)</math> with <math>a = 2 r - u</math> and <math>b = 2 r - v</math>.
    7 KB (1,271 words) - 12:09, 4 January 2024
  • We denote by <math>\left( u, v \right)</math> the coordinates of circle <math>C_0</math>, and <math>r</mat u^2 + v^2 = \left( 8 - r \right)^2 . \hspace{1cm} (1)
    7 KB (1,202 words) - 01:15, 10 June 2023
  • .../math>, define the binary operation <math>\otimes</math> by<cmath>u\otimes v=ac+bdi.</cmath>Suppose <math>z</math> is a complex number such that <math>z
    13 KB (2,107 words) - 22:19, 20 April 2024
  • pair P,Q,R,S,T,U,V,W; P=(0,30); Q=(30,30); R=(40,40); S=(10,40); T=(10,10); U=(40,10); V=(30,0); W=(0,0);
    20 KB (2,846 words) - 12:06, 20 April 2024
  • <math>V=\pi{r^2}h</math> <math>V=\pi{r^2}(14-2r)</math>
    4 KB (697 words) - 17:07, 24 March 2023
  • path v=(5,-0.5)--(5,0)--(5,1)--(6,1)--(6,2)--(6,3)--(6,4)--(7,4); draw(v,p);
    11 KB (1,834 words) - 22:01, 4 January 2024
  • pair o = (0, 0), u = (1, 0), v = 0.8*dir(40), w = dir(70); draw(o--u--(u+v));
    13 KB (2,130 words) - 01:52, 31 January 2024
  • <cmath> V = \frac{1}{3} \cdot x \cdot (S_1 + \sqrt{S_1S_2} + S_2) = \frac{1}{3} \cdot Let the volume without water be <math>V,</math> volume of the pyramid <math>SCGJ</math> be <math>U.</math>
    10 KB (1,574 words) - 16:42, 8 March 2024
  • ...en so are <math>f(V)</math>, <math>V+W</math>, <math>V-W</math>, and <math>V \cdot W</math>.
    5 KB (772 words) - 08:50, 23 February 2023
  • Plugging in <math>A</math> and <math>B</math> gives <math>u=v=0</math>. Plugging in <math>P</math> gives Since it passes through <math>A</math>, for some <math>v, w</math>, the equation of circle <math>(ABP)</math> is,
    7 KB (1,280 words) - 01:22, 6 February 2024
  • Plugging in <math>A</math> and <math>B</math> gives <math>u=v=0</math>. Plugging in <math>P</math> gives
    4 KB (684 words) - 01:55, 6 February 2024
  • <cmath>u = 5y - 1, v = 2x - 3y + 1 \implies u^2 - 5 v^2 = - 4 \implies</cmath>
    15 KB (2,351 words) - 08:28, 20 April 2023
  • https://youtube.com/watch?v=LAuyU2OuVzE ...and <math>w=\frac{2b^3cx_0z_0}{c^2y_0^2-b^2z_0^2}</math>, so <cmath>\frac{v}{w}=\frac{b^2z_0}{c^2y_0},</cmath> which is the required condition for <mat
    14 KB (2,600 words) - 23:37, 10 March 2024
  • ...n c&oacute; biết tại sao SXMN lại c&oacute; sức hấp dẫn như vậy hay kh&ocirc;ng, h&atilde;y c&ugrave;ng l&yacute; giải qua b&agrave;i <p><strong><span style="color: #000000;">XSMN ph&aacute;t triển với mục đ&iacute;ch &Iacute;ch nước lợi nh&agrave;</span></strong><
    11 KB (2,230 words) - 23:24, 9 May 2023
  • 231. Gmaas once demanded Epic Games to give him 5,000,000 V-bucks for his 569823rd birthday. EDIT: This is why Gmaas no longer has an E
    88 KB (14,928 words) - 13:54, 29 April 2024
  • ...math>AB</math> and <math>AC</math> meet the line <math>AU</math> and <math>V</math> and <math>W</math>, respectively. The lines <math>BV</math> and <ma
    736 bytes (124 words) - 23:58, 28 March 2024
  • ...th>f(u) = f(t^{2}+v) = f^{-1}(v)+f(t)^{2}> f^{-1}(v) = f(f(f^{-1}(v))) = f(v)</math>. Hence f is strictly increasing. It is now clear that since <math>f
    1 KB (282 words) - 14:53, 12 March 2024
  • ...sed as <math>(2u-3w, v+4w)</math> with <math>0\le u\le1</math>, <math>0\le v\le1,</math> and <math>0\le w\le1</math>?
    13 KB (1,959 words) - 10:29, 4 April 2024
  • <math>V = \sqrt{(a^2 + b^2 - c^2)(b^2 + c^2 - a^2)(a^2 + c^2 - b^2)/72}</math> ...umes <cmath>[ABCI] + [ABDI] + [ACDI] + [BCDI] = V,</cmath> We have <cmath>V = \frac{4AR}{3}.</cmath> Plugging in and simplifying, we get <math>R = \fra
    13 KB (2,042 words) - 09:34, 3 April 2024
  • label("$v'$", (0, 2.18), NE); ...eed to find <math>v</math> with the largest imaginary part such that <math>v^2</math> lies on <math>\omega</math>.
    6 KB (1,055 words) - 21:58, 28 February 2024
  • https://www.youtube.com/watch?v=dxYw1wYHid4&t=12s ...t, to find the amount of vertices we can use Euler's characteristic, <math>V - E + F = 2</math>, and therefore the amount of vertices is <math>12</math>
    12 KB (2,101 words) - 10:08, 31 March 2024
  • ...nvex polyhedra, <math>V-E+F=2</math>. In our case, <math>V-24+12=2\implies V=14.</math> We know that <math>A+B</math> is the total number of vertices as Note that Euler's formula is <math>V+F-E=2</math>. We know <math>F=12</math> from the question. We also know <ma
    7 KB (1,175 words) - 16:45, 28 January 2024
  • pair K, L, M, N, O, P, Q, R, S, T, U, V; pair K, L, M, N, O, P, Q, R, S, T, U, V;
    19 KB (2,967 words) - 16:56, 24 February 2024
  • ...sed as <math>(2u-3w, v+4w)</math> with <math>0\le u\le1</math>, <math>0\le v\le1,</math> and <math>0\le w\le1</math>? ...h <math>x</math> and <math>y</math>. We first fix <math>u</math> and <math>v</math> to <math>0</math>, and graph <math>(-3w,4w)</math> from <math>0\le w
    6 KB (983 words) - 13:53, 4 April 2024
  • V
    814 bytes (128 words) - 10:36, 11 November 2023
  • Denote <math>m = k u</math> and <math>n = k v</math>. Thus, <math>{\rm gcd} \left( u, v \right) = 1</math>.
    4 KB (616 words) - 16:01, 27 April 2024
  • pair P,Q,R,S,T,U,V,W; P=(0,30); Q=(30,30); R=(40,40); S=(10,40); T=(10,10); U=(40,10); V=(30,0); W=(0,0);
    3 KB (426 words) - 01:50, 18 April 2024
  • For complex number <math>u = a+bi</math> and <math>v = c+di</math> (where <math>i=\sqrt{-1}</math>), define the binary operation <math>u \otimes v = ac + bdi</math>
    1 KB (205 words) - 02:52, 20 November 2023
  • Given the problem \( (f(x) + f(y))(f(u) + f(v)) = f(xu - yv) + f(xv - yu) \), we aim to find a function that satisfies it We start by considering the case when \( x = y = u = v = 0 \).
    2 KB (369 words) - 16:12, 26 March 2024
  • * [[V Olimpiada Iberoamericana de Matemáticas (OIM) ]] Valladolid, España , 19 * [[X Olimpiada Iberoamericana de Matemáticas (OIM) ]] Región V, Chile , 1995
    14 KB (1,323 words) - 12:18, 13 December 2023
  • ...at if <math>x+yt+zt^2 \ne 0</math>, then there exist <math>u</math>, <math>v</math>, and <math>w</math> as rational numbers such that:
    511 bytes (84 words) - 13:28, 13 December 2023
  • <math>V=\sum_{i}^{}2^ik_i=13^3</math> where <math>k_i</math> is the quantity of cub
    2 KB (387 words) - 10:29, 23 December 2023
  • ...lar polygon with <math>n</math> sides, <math>n \ge 4</math>, and let <math>V</math> be a subset of <math>r</math> vertices of the polygon. Show that if vertices are in <math>V</math>.
    396 bytes (66 words) - 04:02, 14 December 2023
  • ...h> by 2000, and <math>y'</math> is the reminder of the division of <math>y+v'</math> by 2001. There are two ships on the board: the Martian one and the
    1 KB (256 words) - 04:26, 14 December 2023
  • ...h> is greater than the ''dragonian distance'' from <math>C</math> to <math>V</math>.
    1,015 bytes (177 words) - 16:49, 14 December 2023
  • 458 bytes (44 words) - 17:51, 14 December 2023
  • X [[Olimpiada Iberoamericana de Matemáticas]] was held in Región V, Chile , 1995
    455 bytes (45 words) - 17:53, 14 December 2023
  • ...here <math>d(v)</math> indicates the distance from <math>A</math> to <math>v</math>. Consider the outgoing edges <math>(A,X)</math> and <math>(A,M)</mat https://www.youtube.com/watch?v=RRTxlduaDs8
    5 KB (887 words) - 14:09, 3 April 2024
  • DVI is an exam in mathematics at the Moscow State University named after M.V. Lomonosov. The first four problems have a standard level. <cmath>\left\{\begin{array}{l} u = \sqrt {2} (x + y),\\v = 3y.\end{array}\right.</cmath>
    32 KB (5,375 words) - 11:43, 5 May 2024
  • https://archifol.io/v/tjqbn89d https://archifol.io/v/brzmkkgh
    273 bytes (44 words) - 21:35, 1 April 2024

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