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  • === Proof 1 === <math>(a+b)^2=c^2+4\left(\frac{1}{2}ab\right)\implies a^2+2ab+b^2=c^2+2ab\implies a^2 + b^2=c^2</math>. {{Ha
    5 KB (886 words) - 13:51, 15 May 2024
  • pair O0=(9,9), O1=(1,1), O2=(3,1), O3=(1,3); draw(Circle(O1,1));
    2 KB (307 words) - 15:30, 30 March 2024
  • <math>\textbf{(A)}\ 1 \qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}\ 4\qquad\textb ==Solution 1==
    1 KB (190 words) - 10:58, 16 June 2023
  • ==Solution 1==
    1 KB (176 words) - 10:58, 16 June 2023
  • <math>\textbf{(A) } -\frac{3}{8} \qquad \textbf{(B) } -\frac{1}{40} \qquad \textbf{(C) } 0 \qquad \textbf{(D) } \frac{3}{8} \qquad \textbf ==Solution 1==
    2 KB (257 words) - 10:57, 16 June 2023
  • A rectangular box has integer side lengths in the ratio <math>1: 3: 4</math>. Which of the following could be the volume of the box? == Solution 1==
    1 KB (184 words) - 13:58, 22 August 2023
  • ..., replacing each occurrence of the digit <math>2</math> by the digit <math>1</math>. Star adds her numbers and Emilio adds his numbers. How much larger ...git and 2 appears 3 times as a units digit, the answer is <math>10\cdot 10+1\cdot 3=\boxed{\textbf{(D) }103.}</math>
    967 bytes (143 words) - 03:18, 27 June 2023
  • == Solution 1 ==
    2 KB (268 words) - 18:19, 27 September 2023
  • ...eft(\frac{1}{2}\right)=30 , \Rightarrow (+40)=70 , \Rightarrow \left(\frac{1}{2}\right)=\boxed{\textbf{(C) }35}</cmath>
    1 KB (169 words) - 14:59, 8 August 2021
  • A triangular array of <math>2016</math> coins has <math>1</math> coin in the first row, <math>2</math> coins in the second row, <math == Solution 1==
    2 KB (315 words) - 15:34, 18 June 2022
  • ...er rectangle is one foot wide, and each of the two shaded regions is <math>1</math> foot wide on all four sides. What is the length in feet of the inner filldraw(rectangle((1,1),(6,4)),gray(0.75));
    2 KB (337 words) - 14:56, 25 June 2023
  • filldraw((7,0)--(8,0)--(8,1)--(0,4)--(0,5)--(1,5)--cycle,gray(0.8)); label("$1$",(1/2,5),dir(90));
    8 KB (1,016 words) - 00:17, 31 December 2023
  • Three distinct integers are selected at random between <math>1</math> and <math>2016</math>, inclusive. Which of the following is a correc ...\dfrac{1}{3}\qquad\textbf{(D)}\ p=\dfrac{1}{3}\qquad\textbf{(E)}\ p>\dfrac{1}{3}</math>
    2 KB (297 words) - 14:54, 25 June 2023
  • ...n a movie theater in a row containing <math>5</math> seats, numbered <math>1</math> to <math>5</math> from left to right. (The directions "left" and "ri <math>\textbf{(A) }1 \qquad \textbf{(B) } 2 \qquad \textbf{(C) } 3 \qquad \textbf{(D) } 4\qquad
    2 KB (402 words) - 14:54, 25 June 2023
  • ...tp://euclidlab.org/programs/archimedean-challenge/1 Archimedean Challenge #1] * [http://www.mindresearch.org/gameathon/ Game-a-thon] challenges students to design and build math games in this national co
    7 KB (792 words) - 10:14, 23 April 2024
  • ...duate or undergraduate mathematics students. The weeks break down into a 2-1-2 schedule: We start with two weeks of Root Class, which consists of a gall
    5 KB (706 words) - 23:49, 29 January 2024
  • ...rint</u>: 1-1.5 (School/Chapter), 2-2.5 (State/National)<br><u>Target:</u> 1.5 (School), 2 (Chapter), 2-2.5 (State/National)}}
    10 KB (1,506 words) - 21:31, 14 May 2024
  • * [[Archimedean Challenge #1]] * [[Archimedean Challenge #1]]
    4 KB (565 words) - 13:24, 13 September 2019
  • ...wo areas of math contests: Grade School (Grades 3, 4, 5, 6, 7, 8 + Algebra 1) and High School (Regional and State Finals). The contest is given in-school May 1-15. Each school sets its own testing date and time within these guidelines.
    8 KB (1,182 words) - 14:26, 3 April 2024
  • *[[Math Kangaroo]] is available to students in grades 1-12. The competition occurs annually during March held at ORU. Students do
    2 KB (279 words) - 19:41, 23 March 2017
  • ...artofproblemsolving.com/store/item/aops-vol1 Art of Problem Solving Volume 1: the Basics]
    5 KB (667 words) - 17:09, 3 July 2023
  • * [https://artofproblemsolving.com/news/articles/establishing-a-positive-culture Establishing a Positive Culture of Expectation in Math Educ * [https://artofproblemsolving.com/news/articles/how-to-write-a-solution How to Write a Math Solution] by [[Richard Rusczyk]] and [[user:MCr
    16 KB (2,152 words) - 21:46, 6 May 2024
  • ...zon.com/gp/product/B09PMLFHX2/ref=ox_sc_act_title_1?smid=ATVPDKIKX0DER&psc=1 Getting Started with Competition Math], a textbook meant for true beginners ...itu-Andreescu/dp/0817643265/ref=sr_1_1?ie=UTF8&s=books&qid=1204029652&sr=1-1 Complex Numbers from A to... Z] by [[Titu Andreescu]]
    24 KB (3,177 words) - 12:53, 20 February 2024
  • ...fproblemsolving.com/store/item/aops-vol1 the Art of Problem Solving Volume 1: the Basics]''
    2 KB (254 words) - 09:04, 25 January 2019
  • ...Response|difficulty=1|breakdown=<u>Division E</u>: 1<br><u>Division M</u>: 1}}
    2 KB (215 words) - 02:54, 18 November 2020
  • ...me=Putnam|region=USA|type=Proof|difficulty=7 - 9|breakdown=<u>Problem A/B, 1/2</u>: 7<br><u>Problem A/B, 3/4</u>: 8<br><u>Problem A/B, 5/6</u>: 9}} ...if the top three students tie, they are all awarded a rank of <math>\frac{1 + 2 + 3}{3}=2</math>.) Before 2019, schools were required to choose their t
    4 KB (623 words) - 13:11, 20 February 2024
  • Khan Academy: AP Physics 1/2
    4 KB (506 words) - 11:46, 6 September 2023
  • ...s/ASIN/0201485419/artofproblems-20 The Art of Computer Programming Volumes 1-3 (boxed set)] by [[D. E. Knuth]]
    2 KB (251 words) - 00:45, 17 November 2023
  • ...Thermodynamics states that the efficiency of heat engines must always be < 1.
    9 KB (1,355 words) - 07:29, 29 September 2021
  • ...c{n^2}{2^n}\right)+\sum_{n=1}^{\infty} \left(\frac{2n}{2^n}\right)+\sum_{n=1}^{\infty} \left(\frac{3}{2^n}\right)</math> \sum_{n=1}^{\infty} \left(\frac{3}{2^n}\right)=x\\
    1 KB (193 words) - 21:13, 18 May 2021
  • ==Overview=={{asy image|<math>1\,2\,3\,4\,5\,6\,7\,8\,9\,0</math>|right|The ten [[digit]]s making up <br />
    6 KB (902 words) - 12:53, 3 September 2019
  • *Distinguished Honor Roll: Awarded to top 1% of scorers on each AMC 8, 10 and 12 respectively. *AIME qualifiers: 960 (1.5%)
    17 KB (1,921 words) - 20:53, 10 May 2024
  • ...>b</math> if <math>a</math> is greater than <math>b</math>, that is, <math>a-b</math> is positive. ...<b</math> if <math>a</math> is smaller than <math>b</math>, that is, <math>a-b</math> is negative.
    12 KB (1,798 words) - 16:20, 14 March 2023
  • ...Info|name=USAMTS|region=USA|type=Proof|difficulty=3-6|breakdown=<u>Problem 1-2</u>: 3-4<br><u>Problem 3-5</u>: 5-6}}
    4 KB (613 words) - 13:08, 18 July 2023
  • ...ty=1 - 1.5|breakdown=<u>Problems 1 - 12</u>: 1<br><u>Problems 13 - 25</u>: 1.5}} The AMC 8 is usually administered on the third week of January. There is a 1-week window for students to take the test.
    4 KB (558 words) - 22:25, 28 April 2024
  • ...gion=USA|type=Multiple Choice|difficulty=1-3|breakdown=<u>Problem 1-5</u>: 1<br><u>Problem 6-20</u>: 2<br><u>Problem 21-25</u>: 3}} ...incorrect questions are worth 0 points, and unanswered questions are worth 1.5 points, to give a total score out of 150 points. From 2002 to 2006, unan
    4 KB (574 words) - 15:28, 22 February 2024
  • ...AMC 12|region=USA|type=Multiple Choice|difficulty=2-4|breakdown=<u>Problem 1-10</u>: 2<br><u>Problem 11-20</u>: 3<br><u>Problem 21-25</u>: 4}} ..., incorrect answers are worth 0 points, and unanswered questions are worth 1.5 points, to give a total score out of 150 points. From 2002 to 2006, the
    4 KB (520 words) - 12:11, 13 March 2024
  • ...c}{3}+d+16=a+b+c+d</math>. This, with some algebra, means that <math>\frac{1}{3}(a+b+c)=8</math>. <math>d</math> must be <math>\boxed{\textbf{(B)} 21}</
    1 KB (200 words) - 23:35, 28 August 2020
  • ...ame=AIME|region=USA|type=Free Response|difficulty=3-6|breakdown=<u>Problem 1-5</u>: 3<br><u>Problem 6-10</u>: 4<br><u>Problem 10-12</u>: 5<br><u>Problem The AIME is a 15 question, 3 hour exam<math>^1</math> taken by high scorers on the [[AMC 10]], [[AMC 12]], and [[USAMTS]]
    8 KB (1,057 words) - 12:02, 25 February 2024
  • draw((-2/3,1/2)--(-sqrt(3)/6,1/2)--(0,0)--(sqrt(3)/6,1/2)--(2/3,1/2)); label("$\frac{1}{2}$",(.5,.25));
    3 KB (415 words) - 18:01, 24 May 2020
  • ==Problem 1== [[2015 IMO Problems/Problem 1|Solution]]
    4 KB (692 words) - 22:33, 15 February 2021
  • ...Info|name=USAMO|region=USA|type=Proof|difficulty=7-9|breakdown=<u>Problem 1/4</u>: 7<br><u>Problem 2/5</u>: 8<br><u>Problem 3/6</u>: 9}}
    6 KB (869 words) - 12:52, 20 February 2024
  • ...dividual</u>: 4 (Problem 6/8), 6 (Problem 10)<br><u>Team</u>: 3.5 (Problem 1-5), 5 (Problem 6-10)}}
    2 KB (267 words) - 17:06, 7 March 2020
  • ...The three teams are the Reals, Naturals, and Primes. Two compete in A and 1 in B... Michigan was also awarded the best shirt design at ARML Iowa 2015.. ...ille, etc.) on the MO ARML team. (eg. the 2008 team fielded 6 from KS, and 1 from IL)
    21 KB (3,500 words) - 18:41, 23 April 2024
  • ....htm American Electroplaters and Surface Finishers Society Scholarship] of 1,500 dollars for undergraduate and graduate students in chemistry and some t
    1 KB (182 words) - 22:00, 4 February 2017
  • ...ican Electroplaters and Surface Finishers Society Scholarship] of <dollar/>1,500 for undergraduate and graduate students in chemistry and some types of ....com/2020-usa-cargo-trailer-scholarship USA Cargo Trailer Scholarship] of $1,500 for students pursuing engineering.
    4 KB (511 words) - 14:57, 16 July 2020
  • ...participate in the Finals round, and they have to solve three problems in 1 hour.
    2 KB (295 words) - 23:19, 5 January 2019
  • *[[Algebra]] 1 *-1 for each incorrect question
    4 KB (632 words) - 17:09, 11 October 2020
  • * [[AoPS Online School/Prealgebra 1 | Prealgebra 1]] — [https://artofproblemsolving.com/school/course/catalog/prealgebra1 De .../Introduction to Algebra A | Introduction to Algebra A]] (formerly Algebra 1) — [https://artofproblemsolving.com/school/course/catalog/algebra-a Detai
    8 KB (965 words) - 03:41, 17 September 2020
  • ...th> positive real weights <math>w_i</math> with sum <math>\sum_{i=1}^n w_i=1</math>, the power mean with exponent <math>t</math>, where <math>t\in\mathb \prod_{i=1}^n a_i^{w_i} &\text{if } t=0 \\
    3 KB (606 words) - 23:59, 1 July 2022
  • ...rem''' states that if [[integer ]]<math>p > 1</math> , then <math>(p-1)! + 1</math> is divisible by <math>p</math> if and only if <math>p</math> is prim ...p-1)! + 1</math>. Therefore <math>p</math> does not divide <math>(p-1)! + 1</math>.
    4 KB (639 words) - 01:53, 2 February 2023
  • ...lutions <math>x,y,z</math> of the equation <math>x^2+5y^2+10z^2=4xy+6yz+2z-1</math>. *Show that <math>\sum_{k=1}^{n}a_k^2 \geq a_1a_2+a_2a_3+\cdots+a_{n-1}a_n+a_na_1</math>. [[Inequality_Introductory_Problem_2|Solution]]
    3 KB (560 words) - 22:51, 13 January 2024
  • For example, if I wanted to find the average of the numbers 3, 1, 4, 1, and 5, I would compute: <center><math> \frac{3+1+4+1+5}{5} = \frac{14}{5}.</math></center>
    699 bytes (110 words) - 12:44, 20 September 2015
  • What is the value of <math>x</math> if <math>x=1+\dfrac{1}{x}</math>
    2 KB (422 words) - 16:20, 5 March 2023
  • <cmath>[ABC]=\frac{ab}{2}\sqrt{1-\cos^2 C}.</cmath> <math>[ABC]=\frac{ab}{2}\sqrt{1-\left(\frac{a^2+b^2-c^2}{2ab}\right)^2}.</math>
    4 KB (675 words) - 00:05, 22 January 2024
  • * <math>x^{-1}+2+3x+x^2</math> * <math>x^{1/3}=\sqrt[3]{x}</math>
    6 KB (1,100 words) - 01:44, 17 January 2024
  • ...h> are integer constants, and the coefficient of xy must be 1(If it is not 1, then divide the coefficient off of the equation.). According to Simon's Fa ...y)</math> that are solutions to the equation <math>\frac{4}{x}+\frac{5}{y}=1</math>. (2021 CEMC Galois #4b)
    7 KB (1,107 words) - 07:35, 26 March 2024
  • The test is scored as 5 points for every correct response, 1 point for a blank response, and 0 points for an incorrect response.
    972 bytes (141 words) - 11:12, 30 September 2018
  • <cmath>a^n-b^n=(a-b)(a^{n-1}+a^{n-2}b + \cdots + ab^{n-2} + b^{n-1})</cmath> ...this creates the difference of squares factorization, <cmath>a^2-b^2=(a+b)(a-b)</cmath>
    3 KB (532 words) - 22:00, 13 January 2024
  • ...e|primes]] <math>p_1, p_2,\ldots, p_n</math>. Let <math>N=p_1p_2p_3...p_n+1</math>. <math>N</math> is not divisible by any of the known primes since i
    2 KB (374 words) - 14:01, 21 August 2022
  • ...e sum of the [[series]] <math>\frac11 + \frac14 + \frac19 + \cdots + \frac{1}{n^2} + \cdots</math><br> ...{\pi}\right)\left(1+\frac{x}{\pi}\right)\left(1-\frac{x}{2\pi}\right)\left(1+\frac{x}{2\pi}\right)\cdots</math><br>
    2 KB (314 words) - 06:45, 1 May 2014
  • In [[combinatorics]], the '''pigeonhole principle''' states that if <math>n+1</math> or more pigeons are placed into <math>n</math> holes, one hole must ...ontain at most one ball implies that <math>b_r \leq 1</math> for all <math>1 \leq r \leq n</math>, so <cmath>b_1 + b_1 + \cdots + b_n \geq n.</cmath> Ho
    11 KB (1,985 words) - 21:03, 5 August 2023
  • Next, we factor out our common terms to get <math>x(x-1)-2(x-1)=0</math>. ...<math>(x-1)(x-2)=0</math>. By the zero-product property, either <math> (x-1) </math> or <math> (x-2) </math> equals zero.
    2 KB (264 words) - 12:04, 15 July 2021
  • ...r than 1. That is, their [[greatest common divisor]] is <math>\gcd(m, n) = 1</math>. Equivalently, <math>m</math> and <math>n</math> must have no [[pri ...r difference <math>(n+1)-n = 1</math>, which is impossible since <math>p > 1</math>.
    2 KB (245 words) - 15:51, 25 February 2020
  • \textbf{(D) }\ 1 \qquad We can then try <math>(x^2+3x+1)=x^4+6x^3+11x^2+6x+1</math>.
    3 KB (571 words) - 00:42, 22 October 2021
  • ...>\int \sqrt{a^2+x^2}\,dx</math>, we make use of the identity <math>\tan^2x+1=\sec^2x</math>. Set <math>x=a\tan\theta</math> and the radical will go awa Making use of the identity <math>\sin^2\theta+\cos^2\theta=1</math>, simply let <math>x=a\sin\theta</math>.
    1 KB (173 words) - 18:42, 30 May 2021
  • ...eometric mean of the numbers 6, 4, 1 and 2 is <math>\sqrt[4]{6\cdot 4\cdot 1 \cdot 2} = \sqrt[4]{48} = 2\sqrt[4]{3}</math>. MC("\sqrt{ab}",D(A--M,orange+linewidth(1)),W);
    2 KB (282 words) - 22:04, 11 July 2008
  • ...gain, <math>|A\cap C|</math> would be putting five guys in order, so <math>1!\binom{6}{5}=6</math>. <math>|A\cap D|</math> is just choosing <math>3</mat ...>, <math>|A\cap C\cap D|</math> is again ordering everybody which is <math>1</math>, and <math>|B\cap C\cap D|</math> is the same as <math>|A\cap B\cap
    9 KB (1,703 words) - 07:25, 24 March 2024
  • Googol is a huge number. It has a 1 followed by 100 zeroes or <math>10^{100}.</math>
    84 bytes (14 words) - 10:46, 25 October 2020
  • * <math>\binom{n-1}{r-1}+\binom{n-1}{r}=\binom{n}{r}</math> * <math>\binom{n}{r}=\frac{n}{r}\binom{n-1}{r-1}</math>
    4 KB (615 words) - 11:43, 21 May 2021
  • ...row (a-1)(b-1)=2</math> from whence we have <math>(a,b,c)\in\{(2,3,1),(3,2,1)\}</math>. ...b\geq 6c</math> we have <math>6c\leq 2c+6\Rightarrow c\leq3/2\Rightarrow c=1</math>; a contradiction since <math>c\geq 2</math>.
    2 KB (332 words) - 09:37, 30 December 2021
  • ...a constant <math>t</math> such that <math>a_i = t b_i</math> for all <math>1 \leq i \leq n</math>, or if one list consists of only zeroes. Along with th ...a^2b^2</math>. The inequality then follows from <math> |\cos\theta | \le 1 </math>, with equality when one of <math> \mathbf{a,b} </math> is a multipl
    13 KB (2,048 words) - 15:28, 22 February 2024
  • ...[recursion|recursive definition]] for the factorial is <math>n!=n \cdot (n-1)!</math>. * <math>0! = 1</math> (remember! this is 1, not 0! (the '!' was an exclamation mark, not a factorial sign))
    10 KB (809 words) - 16:40, 17 March 2024
  • ...ng about the roots of a given [[polynomial]] <math>p(x)=a_nx^n+a_{n-1}x^{n-1}+...+a_0</math> of degree <math>n</math> with all the coefficients being re ...integer such that <math>k\geq\frac{n-2}{4}</math>, then there are <math>2k+1</math> pairs of complex conjugate roots and <math>n-4k+2</math> real roots.
    4 KB (734 words) - 19:19, 10 October 2023
  • <cmath>\frac{PB}{CP} \cdot \frac{QC}{QA} \cdot \frac{AR}{RB} = 1.</cmath> ...;label("C",C,(1,0));label("P",P,(0,-1));label("Q",Q,(1,0));label("R",R,(-1,1));
    5 KB (804 words) - 03:01, 12 June 2023
  • | [[South Carolina ARML]] (South Carolina #1)
    19 KB (2,632 words) - 14:31, 12 June 2022
  • ...t [[divisibility|divisible]] by <math>{p}</math>, then <math>a^{p-1}\equiv 1 \pmod {p}</math>. ...denotes [[Euler's totient function]]. In particular, <math>\varphi(p) = p-1</math> for prime numbers <math>p</math>. In turn, this is a special case of
    16 KB (2,658 words) - 16:02, 8 May 2024
  • xaxis(-9,9,Ticks(f, 1.0)); yaxis(-9,9,Ticks(f, 1.0));
    3 KB (551 words) - 16:22, 13 September 2023
  • ...\sum_{i=1}^{n}a_ib_i\right)\geq\left(\sum_{i=1}^{n}a_i\right)\left(\sum_{i=1}^{n}b_i\right)</math>. <math> b_n\geq b_{n-1}\geq ... \geq b_1 </math> then:
    1 KB (214 words) - 20:32, 13 March 2022
  • ...er [[relatively prime]] to <math>a</math>, then <math>{a}^{\phi (m)}\equiv 1 \pmod {m}</math>. ...hi(m)} \pmod{m} </math> <math> \implies </math> <math> a^{\phi (m)} \equiv 1 \pmod{m}</math> as desired. Note that dividing by <math> n_1 n_2 ... n_{\ph
    3 KB (542 words) - 17:45, 21 March 2023
  • .../math> and [[perimeter]] <math>P</math>, then <math>\frac{4\pi A}{P^2} \le 1</math>. This means that given a perimeter <math>P</math> for a plane figure ...o <math>2\sin A \cos B<2\sin A</math>, which is equivalent to <math>\cos B<1</math>. Since this is always true for <math>0<B<180</math>, this inequality
    7 KB (1,296 words) - 14:22, 22 October 2023
  • Substituting <math>\sin^2B=1-\cos^2B</math> results in <cmath>4[ABCD]^2=(1-\cos^2B)(ab+cd)^2=(ab+cd)^2-\cos^2B(ab+cd)^2</cmath>
    3 KB (465 words) - 18:31, 3 July 2023
  • == Proof 1 == ...<math> ABCDEFG </math>, prove that: <math> \frac{1}{AB}=\frac{1}{AC}+\frac{1}{AE} </math>.
    7 KB (1,198 words) - 20:39, 9 March 2024
  • ...mbers is the sum of all products of <math>k</math> of those numbers (<math>1 \leq k \leq n</math>). For example, if <math>n = 4</math>, and our set of ...)^nS_n</math>, and the coefficient of the <math>x^k</math> term is <math>(-1)^{n-k}S_{n-k}</math>, where the symmetric sums are taken over the roots of
    2 KB (275 words) - 12:51, 26 July 2023
  • <cmath>z'=\frac{az+b}{cz+d},\quad a,b,c,d\in\mathbb{Z}, ad-bc=1.</cmath>
    5 KB (849 words) - 16:14, 18 May 2021
  • <math> \sqrt{x+\sqrt{2x-1}} + \sqrt{x-\sqrt{2x-1}} = A,</math> given (a) <math>A=\sqrt{2}</math>, (b) <math>A=1</math>, (c) <math>A=2</math>, where only non-negative real numbers are admi
    3 KB (466 words) - 12:04, 12 April 2024
  • ...> is defined to be: <math> \frac{n} {\frac{1}{x_1}+\frac{1}{x_2}+...+\frac{1}{x_n}}</math>. ..._1\cdot x_2 \cdots x_n}\ge \frac{n} {\frac{1}{x_1}+\frac{1}{x_2}+...+\frac{1}{x_n}} </math>
    1 KB (196 words) - 00:49, 6 January 2021
  • ...(1-\frac{1}{p_1} \right) \left(1-\frac{1}{p_2} \right)\cdots \left(1-\frac{1}{p_m}\right).</cmath> ...fine the [[prime factorization]] of <math> n </math> as <math> n =\prod_{i=1}^{m}p_i^{e_i} =p_1^{e_1}p_2^{e_2}\cdots p_m^{e_m} </math> where the <math>p
    5 KB (898 words) - 19:12, 28 January 2024
  • ..., <math>(\Omega, \mathfrak{a})</math>. <math>\mathit{P}:\mathfrak{a}\to [0,1]</math> is an assignment with certain properties (it is a special kind of [ <math>\mathit{P}(\{H, T\})=1</math>.
    4 KB (588 words) - 12:47, 2 October 2022
  • <cmath>1+2+3+4+5+\sin \pi = \frac{5\cdot 6}{2}+0=15.</cmath>
    1 KB (164 words) - 19:09, 14 February 2024
  • * The positive divisors of <math>35</math> are <math>1</math>, <math>5</math>, <math>7</math>, and <math>35</math>.
    2 KB (277 words) - 16:21, 29 April 2023
  • ...in increasing order, then the maximum sum is just <math>-a_1b_k - a_2b_{k-1} + \ldots</math>. Thus, by negating all values the inequality follows.
    5 KB (804 words) - 13:54, 26 January 2023
  • ...umber line. It can have any value. Some examples of real numbers are:<math>1, 2, -23.25, 0, \frac{\pi}{\phi}</math>, and so on. Numbers that are not rea (1) <math>\alpha\neq\mathbb{Q}</math> and <math>\alpha</math> is [[bounded]] a
    3 KB (496 words) - 23:22, 5 January 2022
  • Rule 1: Partition <math>N</math> into 3 digit numbers from the right (<math>d_3d_ [[Divisibility rules/Rule 1 for 7 proof | Proof]]
    8 KB (1,315 words) - 18:18, 2 March 2024
  • ...works for <math>n=1+1=2</math>, which in turn means it works for <math>n=2+1=3</math>, and so on. ...+1)}{2}</math> (the <math>n</math>th triangular number is defined as <math>1+2+\cdots +n</math>; imagine an [[equilateral polygon | equilateral]] [[tria
    5 KB (768 words) - 20:45, 1 September 2022
  • ...wever, <cmath>\angle BIL = \angle BAI + \angle ABI = \frac{1}{2} A + \frac{1}{2} B.</cmath> Hence, <math>\triangle BIL</math> is isosceles, so <math>LB
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  • [[Image:Acute_orthic_triangle.png|thumb|right|300px|Case 1: <math>\triangle ABC</math> is acute.]] ...enter of <math>\triangle DEF</math>, <math>\angle EDC = 90^{\circ} - \frac{1}{2} \angle D</math>. Thus, <math>\angle ADC = 90^{\circ}</math>, and becaus
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  • {{asy image|<asy>draw((0,1)--(2,0)--(3,2)--cycle);</asy>|right|A triangle.}} {{asy image|<asy>draw((0,0)--(1,0)--(0.5,0.5)--cycle);</asy>|right|An isosceles triangle.}}
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  • ...use the recursive formula <math>GCD(a_1,\dots,a_n)=GCD(GCD(a_1,\dots,a_{n-1}),a_n)</math>.
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  • Here is MATHCOUNTS 2008 National Target #1: Try to solve this. ...According to the formula we get 2 handshakes, but wait, we will have only 1 handshake between two persons. That means we have overcounted somewhere.
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  • === Example 1 === ...first digit is, we know that it removes one option, so there are <math>8 - 1 = 7</math> options for the second digit.
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  • ...math> and let <math>a_1,\dots, a_n\ge 0</math> satisfy <math>a_1+\dots+a_n=1</math>. Then Let <math>\bar{x}=\sum_{i=1}^n a_ix_i</math>.
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  • === Example 1 === '''Case 1''': The word is one letter long. Clearly, there are <math>5</math> of these
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  • <math>r_{n-1} \pmod {r_n} \equiv 0</math><br> for <math>r_{k+1} < r_k < r_{k-1}</math><br>
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  • ...here the distance from a line (the directrix) is some number <math>0 < e < 1</math> times the distance to some fixed point (the focus). ...nce away from a point (focus) and a line (called the directrix) (<math>e = 1</math>).
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  • ...ath>A(k)={n \choose k}</math>, then we have <math>{n \choose 0}+{n \choose 1}x + {n \choose 2}x^2+\cdots+</math><math>{n \choose n}x^n</math>. .....+{n \choose n}=2^n</math>(let <math>{x}=1</math>), also <math>{n \choose 1}+{n \choose 3}+\cdots={n \choose 0}+{n \choose 2}+\cdots</math>.
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  • ...ath>, with coefficients <math>1 = \binom{5}{0}</math>, <math>5 = \binom{5}{1}</math>, <math>10 = \binom{5}{2}</math>, etc. ...(a+b)^{n} = \sum_{k=0}^{n}\binom{n}{k}a^{n-k}b^{k}</math>, <cmath>(a+b)^{n+1} = (\sum_{k=0}^{n}\binom{n}{k}a^{n-k}b^{k})(a+b)</cmath>
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  • ...integer]] <math>p>1</math> whose only positive [[divisor | divisors]] are 1 and itself. Note that <math>1</math> is usually defined as being neither prime nor [[composite number|com
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  • ...early values of the sequence in terms of previous values: <math>F_0=1, F_1=1, F_2=2, F_3=3, F_4=5, F_5=8</math>, and so on. ...defined recursively by <math>a_0 = 1</math> and <math>a_n = 2\cdot a_{n - 1}</math> for <math>n > 0</math> also has the closed-form definition <math>a_
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  • ...exactly one value in the second. For instance, one function may map 1 to 1, 2 to 4, 3 to 9, 4 to 16, and so on. This function has the rule that it ta ...'.) Often the inverse of a function <math>f</math> is denoted by <math>f^{-1}</math>.
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  • ...bility it does not happen is one. Thus, we have the identity <cmath>P(A) = 1 - P(A^c).</cmath> Like its counting analog, complementary probability often === Example 1 ===
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  • <math>{n \choose k}={n-1\choose k-1}+{n-1\choose k}</math> ...s added to the number of ways to choose <math>k</math> things from <math>n-1</math> things.
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  • ...ath> are integers, then their sum <math>a+b</math>, their difference <math>a-b</math>, and their product <math>ab</math> are all integers (that is, the i ...</math> bits), which limits their maximum value (typically to <math>2^{31}-1</math> for signed <math>32</math>-bit integers). Integers in Python can be
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  • * [[2000 AIME I Problems/Problem 1]]
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  • ...''' is a [[positive integer]] with at least one [[divisor]] different from 1 and itself. Some composite numbers are <math>4=2^2</math> and <math>12=2\t Every positive integer either is prime, composite, or 1.
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  • A '''natural number''' is any positive [[integer]]: <math>\text{1, 2, 3, 4, 5, 6, 7,\dots}</math>. The set of '''natural numbers''', denoted
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  • '''Case 1:''' The circle's area is greater than the triangle's area. ...han the radius so <math>a<r</math>. Therefore <math> P=\frac{1}{2}ap<\frac{1}{2}r\cdot 2\pi r=T</math>. However it cannot be both <math>P>T</math> and <
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  • MC(90,"\mbox{semiminor axis}",7,D((0,0)--(0,3),green+linewidth(1)),E); MC("\mbox{semimajor axis}",7,D((0,0)--(5,0),red+linewidth(1)),S);
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  • ...ath>d(n)=(\alpha_{1} + 1)\cdot(\alpha_{2} + 1)\cdot\dots\cdot(\alpha_{m} + 1)</math>. It is often useful to know that this expression grows slower than * <math>{\sum_{n=1}^N d(n)=\left\lfloor\frac N1\right\rfloor+\left\lfloor\frac N2\right\rfloor
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  • ...number can be rewritten as <math>2746_{10}=2\cdot10^3+7\cdot10^2+4\cdot10^1+6\cdot10^0.</math> ...six <math>10^0</math>'s, the second digit tells us there are four <math>10^1</math>'s, the third digit tells us there are seven <math>10^2</math>'s, and
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  • ...ong computer programmers. It has just two digits: <math>0</math> and <math>1</math>. [[Hexadecimal]] is base 16. The digits in hexadecimal are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, and F. One of its common uses is f
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  • ...thcal{P}</math> is defined as <math>\|\mathcal{P}\|=\sup\{x_i-x_{i-1}\}_{i=1}^n</math> ...he set of ordered pairs <math>\mathcal{\dot{P}}=\{([x_{i-1},x_i],t_i)\}_{i=1}^n</math>.
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  • Consider the function <math>f:[0,1]\rightarrow\mathbb{R}</math> <math>f\left( \frac{1}{n}\right) =n\forall n\in\mathbb{N}</math>
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  • {{duplicate|[[2001 AMC 12 Problems|2001 AMC 12 #1]] and [[2001 AMC 10 Problems|2001 AMC 10 #3]]}}
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  • {{AMC12 box|year=2001|num-b=1|num-a=3}}
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  • A = (-1, 1); B = (1, 1);
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  • ...ngaroo is an international mathematical competition for students in grades 1 through 12. The competition consists of a single round that is taken on th Any student that is currently enrolled in grades 1 through 12 (or homeschooled equivalent) is eligible to participate. They m
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  • Contest #1 - October 10, 2019
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  • <math>12 = 2^2\cdot 3^1</math> <math>15 = 3^1\cdot 5^1</math>
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  • ...llet}&&x^{2n+1}+y^{2n+1}&=(x+y)(x^{2n}-x^{2n-1}y+x^{2n-2}y^2-\ldots-xy^{2n-1}+y^{2n})\\ \text{\textbullet}&&x^{n}-y^{n}&=(x-y)(x^{n-1}+x^{n-2}y+\cdots +xy^{n-2}+y^{n-1})
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  • ...evel I</u>: 0.5 - 1<br><u>Level II</u>: 0.5 - 1.5<br><u>Level III</u>: 1 - 1.5}} * Level I: For grades 1 and 2.
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  • == Individual Round - Part 1 == * 1 point is awarded for each question left blank
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  • BD = \frac{BA \cdot DC }{AP} \; (1) ...both sides of the inequality by <math>BD</math> and using equations <math>(1) </math> and <math>(2) </math> gives us
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  • A = (1, 2); draw(B--M, StickIntervalMarker(1));
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  • ...e most surprising places, such as in the sum <math>\sum_{n=1}^\infty \frac{1}{n^2}=\frac{\pi^2}{6}</math>. Some common [[fraction]]al approximations fo ...rmula for pi is <math>4\left( \sum_{i = 0}^\infty (-1)^i \left(\frac{1}{2n+1}\right)\right) </math>. This can be computed to the desired degree of accur
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  • ...ently in mathematical writing, often to represent the constant <math>\frac{1+\sqrt{5}}{2}</math>. (The Greek letter [[Tau]] (<math>\tau</math>) was also ...as well as the positive solution of the [[quadratic equation]] <math>x^2-x-1=0</math>.
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  • ...term is the sum of the two preceding it. The first few terms are <math>1, 1, 2, 3, 5, 8, 13, 21, 34, 55,...</math>. ...[[recursion|recursively]] as <math>F_1 = F_2 = 1</math> and <math>F_n=F_{n-1}+F_{n-2}</math> for <math>n \geq 3</math>. This is the simplest nontrivial
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  • ...sequence <math>(5,1)</math> majorizes <math>(4,2)</math> (as <math>5>4, 5+1=4+2</math>), Muirhead's inequality states that for any positive <math>x,y</ <cmath>x^5y^1+y^5x^1\geq x^4y^2+y^4x^2</cmath>
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  • ...y of <math>\{3, 4\}</math> is 2, the cardinality of <math>\{1, \{2, 3\}, \{1, 2, 3\}\}</math> is 3, and the cardinality of the [[empty set]] is 0.
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  • ...thbb R</math>, <math>f(x)=x^2</math> is not an injection (<math>f(-1)=f(1)=1</math>), the function <math>g:[0,\infty)\to\mathbb R</math>, <math>g(x)=x^2
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  • ...ve.) Interpret the distance that the object travels between times <math>t=1</math> and <math>t=2</math> geometrically, as an area under a curve. ...is the amount that <math>F</math> changes on the interval <math>[x_i, x_{i+1}]</math>, then <math>\Delta F_i \approx F'(x_i)\Delta x</math>.
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  • ...-- it will have "degenerated" from an <math>n</math>-gon to an <math>(n - 1)</math>-gon. (In the case of triangles, this will result in either a line
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  • ...h>A</math> and perimeter <math>P</math> then <math>\frac{4\pi A}{P^2} \leq 1</math>. This means that given a perimeter <math>P</math> for a plane figure
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  • ...s://seasonsbeachcottage.com/mental-health-education-scholarship-2023-round-1 Mental health Education Annual Scholarship 2023] Applicants must be current ...g Scholarship] Zampi, Inc. A small business marketing platform is offering 1,000 dollar scholarship. To enter, simple create a small business marketing
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  • * [[Best Buy @15 Scholarship]] of <dollar/>1,000 for students in grades 9-12. [https://www.at15.com/contests_scholarship
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  • A pyramid has a square base with sides of length <math>1</math> and has lateral faces that are equilateral triangles. A cube is plac == Solution 1 ==
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  • == Solution 1==
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  • <math>[ABCD]=\frac{1}{4} \cdot \sqrt{4p^2q^2-(b^2+d^2-a^2-c^2)^2}</math>. ...vec{c} - \vec{d}</math>. The area of any such quadrilateral is <math>\frac{1}{2} |\vec{p} \times \vec{q}|</math>.
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  • pen p=linewidth(1); MA("\theta",(5,-1),(2,3),(4,6),0.3,9,yellow);
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  • ...bers. ex. :<cmath>((((((3^5)^6)^7)^8)^9)^{10})^{11}=\underbrace{1177\ldots 1}_{\text{793549 digits}}</cmath> would be a pain to have to calculate any ti <cmath>\log_4(5)\approx 1.160964047443681173935159715\ldots</cmath>
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  • ==Proof 1== label("A",A,(1,0));
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  • <cmath>a^r(a-b)(a-c)+b^r(b-a)(b-c)+c^r(c-a)(c-b) \geq 0</cmath> The <math>r=1</math> case yields the well-known inequality:
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  • * <math>\sin^2x + \cos^2x = 1</math> * <math>1 + \cot^2x = \csc^2x</math>
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  • ...>\sqrt{2}</math> as the length of a diagonal of a square with side lengths 1 in the sixth century <math>B.C</math>. The Pythagoreans lived by the doctri <math>3\frac{10}{71}</math> <math>to</math> <math>3\frac{1}{7}</math>.
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  • ...numbers''' arise when we try to solve [[equation]]s such as <math> x^2 = -1 </math>. ...this addition, we are not only able to find the solutions of <math> x^2 = -1 </math> but we can now find ''all'' solutions to ''every'' polynomial. (Se
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  • ...ecause every integer <math>a</math> can be represented as <math>a=\frac{a}{1}</math>
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  • ...the [[complex number|complex]] [[root]]s of the [[polynomial]] <math> x^n=1 </math>. ...ik}</math>. The magnitude of the RHS is 1, making <math>r^n=1\Rightarrow r=1</math> (magnitude is always expressed as a positive real number). This lea
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  • markangle(n=1,radius=20,D,A,F,green); markangle(n=1,radius=22,F,A,B,green);
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  • * [[2005_Austrian_Mathematical_Olympiad_Final_Round-Part 1/Problem 5]]
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  • === Method 1 === real r = 1;
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  • ...<math>\mathbb{N}</math> corresponds to the sequence <math>X = (x_n) = (0, 1, 4, 9, 16, \ldots)</math>. A classic example of convergence would be to show that <math>1/n\to 0</math> as <math>n\to \infty</math>.
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  • ...ratio <math>-1/2</math>; however, <math>1, 3, 9, -27</math> and <math>-3, 1, 5, 9, \ldots</math> are not geometric sequences, as the ratio between cons ...ogression if and only if <math>a_2 / a_1 = a_3 / a_2 = \cdots = a_n / a_{n-1}</math>. A similar definition holds for infinite geometric sequences. It ap
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  • ...h>1, 2, 3, 4</math> is an arithmetic sequence with common difference <math>1</math> and <math>99, 91, 83, 75</math> is an arithmetic sequence with commo ...ogression if and only if <math>a_2 - a_1 = a_3 - a_2 = \cdots = a_n - a_{n-1}</math>. A similar definition holds for infinite arithmetic sequences. It a
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  • ...n unique factorization in [[ring]]s of the form <math>\mathbb{Z}[\sqrt[n]{-1}]</math>. Unfortunately, this is not often the case. In fact, it has now
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  • * A homothety with factor <math>-1</math> is a <math>180^\circ</math> rotation about the center.
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  • ...a piece of length <math>k_i</math> from the end of leg <math>L_i \; (i = 1,2,3,4)</math> and still have a stable table? == Solution 1 ==
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  • ...0 AMC 12 Problems|2000 AMC 12 #1]] and [[2000 AMC 10 Problems|2000 AMC 10 #1]]}} == Solution 1 (Verifying the Statement)==
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  • ...there will always be an infinite number of solutions when <math>\gcd(a,b)=1</math>. If <math>\gcd(a,b)\nmid c</math>, then there are no solutions to t .../math> is an [[odd]] number, then <math>m, \frac {m^2 -1}{2}, \frac {m^2 + 1}{2}</math> is a Pythagorean triple.
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  • ...ices to the [[circumcenter]]. This creates a triangle that is <math>\frac{1}{n},</math> of the total area (consider the regular [[octagon]] below as an ..._b^{-1})(H-h_c^{-1})}</math>, where <math>H=\frac{(h_a^{-1}+h_b^{-1}+h_c^{-1})}{2}</math> and the triangle has altitudes <math>h_a</math>, <math>h_b</ma
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  • ...the denominator such as <math>\frac{3}{3}</math> is always equal to <math>1</math>. ...d denominator by the same quantity (since we're essentially multiplying by 1).
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  • ...'.) Often the inverse of a function <math>f</math> is denoted by <math>f^{-1}</math>. ...le of such a function is <math>f(x) = 1/x</math> because <math>f(f(x)) = f(1/x) = x</math>. Cyclic functions can significantly help in solving function
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  • A=(0,1); C=(1,0);
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  • ...loor+\left\lfloor a+\frac{1}{n}\right\rfloor+\ldots+\left\lfloor a+\frac{n-1}{n}\right\rfloor</cmath> ...te the largest integer not exceeding <math>x</math>. For example, <math>[2.1]=2</math>, <math>[4]=4</math> and <math>[5.7]=5</math>. How many positive i
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  • ...sum of the two numbers appearing above it. For example, <math>{5 \choose 1}+{5 \choose 2} = 5 + 10 = 15 = {6 \choose 2}</math>. This property allows ...math>{6 \choose 0}+{5 \choose 1}+{4 \choose 2}+{3 \choose 3} = 1 + 5 + 6 + 1 = 13 = F(7)</math>. A "shallow diagonal" is plotted in the diagram.
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  • <center><math> P(x) = a_nx^n + a_{n-1}x^{n-1} + \cdots + a_1x + a_0</math></center> <cmath>a_nP_1 + a_{n-1} = 0</cmath>
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  • ...words, we want to divide by 2 four times. Therefore, <math> 2^{-4}=\frac 1{2^4}.</math> * <math>b^0 = 1</math> if <math>b \neq 0</math>
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  • ...en denominator <math>q\ge 1</math> with an error not exceeding <math>\frac 1{2q}</math>. ...interval <math>\left[qx-\frac12,qx+\frac12\right]</math> has length <math>1</math> and, therefore, contains at least one integer. Choosing <math>p</mat
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  • ...d as the reciprocal of the sine of <math>A</math>. <cmath>\csc (A) = \frac{1}{\sin (x)} = \frac{\textrm{hypotenuse}}{\textrm{opposite}} = \frac{c}{a}.</ ...as the reciprocal of the cosine of <math>A</math>. <cmath>\sec (A) = \frac{1}{\cos (x)} = \frac{\textrm{hypotenuse}}{\textrm{adjacent}} = \frac{c}{b}.</
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  • ...>e</math> such that <math>\ln e=1</math>, where <math>\ln x=\int_1^x \frac{1}{t} \, dt</math>. It has been shown to be both [[irrational]] and [[transce ...tion such that <math>\frac{d}{dx} \exp(x)=\exp(x)</math> and <math>\exp(0)=1</math> is equal to <math>e^x</math>.
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  • :<math>f\left( x \right) = a\left( {{1 \over 2}} \right)^{{x \over h}} :If <math>b > 1</math>, then the function will show growth.
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  • ...three instructional sessions: 8:30 AM - 10:00 AM, 10:15 AM - 11:45 AM, and 1:15 PM - 2:45 PM. Classes usually consist of a lecture followed by a problem ...ered in place of the afternoon lecture, and is graded with comments within 1-2 days.
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  • ...h> f^{(n)}(z_0)=\frac{n!}{2\pi i} \oint_\Gamma \frac{f(z)\; dz}{(z-z_0)^{n+1}}. </cmath>
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  • ...cdots+x_a^{n_4}}{a}}</cmath> where <math>n_1>1,~~0<n_2<1,~~-1<n_3<0,~~n_4<-1</math>, and <math>n</math> is the root mean power. ...s greater than or equal to 1. This creates the indeterminate form of <math>1^{\infty}</math>. Then, we can say that the limit as x goes to 0, the result
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  • <math>\sum_{i=1}^{\infty}\frac{1}{i}=1+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\cdots</math> <math>\sum_{i=1}^{\infty}\frac{(-1)^{i+1}}{i}=1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+\cdots</math> , though, approaches <math>\ln 2</math>.
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  • He considered 1 to be a prime number, a [[mathematical convention|convention]] subsequently ...m</math> and <math>n-m</math> simultaneously being prime to be <math>\frac{1}{\ln m \cdot \ln (n-m)}</math>. This heuristic is non-rigorous for a numbe
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  • ...1}{5}+\frac{1}{5}+\frac{1}{7}+\frac{1}{11}+\frac{1}{13}+\frac{1}{17}+\frac{1}{19}+\cdots</math></center> ...y if one of variables is 0 will the factorization be trivial (contain only 1 and itself).
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  • === 2 = 1 === <div style="text-align:center"><math> 2 = 1 </math> (dividing by <math>a^2-ab</math>)</div>
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  • ...[[root |zero]]s of the [[Riemann zeta function]] have [[real part]] <math>1/2</math>. From the [[functional equation]] for the zeta function, it is eas ...atement of the Riemann hypothesis is that <math>\pi(x)=\mathrm{Li}(x)+O(x^{1/2}\ln(x))</math>.
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  • ...\mathrm{ and }\ a\ \mathrm{\ is\ a\ quadratic\ residue\ modulo\ }\ p, \\ -1 & \mathrm{if }\ p\nmid a\ \mathrm{ and }\ a\ \mathrm{\ is\ a\ quadratic\ no ...left(\frac{p}{q}\right)\left(\frac{q}{p}\right)=(-1)^{\frac{p-1}{2}\frac{q-1}{2}}</math>. This is known as the [[Quadratic Reciprocity Theorem]].
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  • ''Proof.'' We have already proven the theorem for a <math>1</math>-sphere (i.e., a circle), so it only remains to prove the theorem for ==== Problem 1 ====
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  • ...loss of generality, suppose that <math>P</math> is [[monic]]. Then <math>1/P(z)</math> is an [[entire]] function; we wish to show that it is bounded. ...absolute values of the coefficients of <math>P</math>, so that <math>R \ge 1</math>. Then for <math>\lvert z \rvert \ge R</math>,
    5 KB (832 words) - 14:22, 11 January 2024
  • ...>, the sequence <math>\{n,f(n),f(f(n)),f(f(f(n))),\ldots\}</math> contains 1. This conjecture is still open. Some people have described it as the easies Observing that if <math>n=2m+1</math> then <math>3n+1=6m+4</math>, as well as: <cmath>{6m+4\over 2}=3m+2</cmath> we can then obse
    1 KB (231 words) - 19:45, 24 February 2020
  • ...ynomial]] with [[rational]] [[coefficient]]s. Examples include <math>\frac{1}{3}</math>, <math>\sqrt{2}+\sqrt{3}</math>, <math>i</math>, and <math>\frac
    1,006 bytes (151 words) - 21:56, 22 April 2022
  • D=intersectionpoint(A+0.1*expi((angle(B-A)+angle(C-A))/2)--A+20*expi((angle(B-A)+angle(C-A))/2), circ dot(A^^B^^C^^D^^I);label("A",A,(0,1));label("B",B,(-1,0));label("C",C,(1,0));
    2 KB (381 words) - 19:38, 24 November 2011
  • ...+ \ldots + a_n = \left(\sum_{j=1}^n a_j\right) - a_i</math> for <math>i = 1, 2 \ldots, n</math>. Expressing the inequality in this form leads to <math
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  • ...for all <math> 1 \le k \le n </math>, <math> \sum_{i=1}^{k}a_i \ge \sum_{i=1}^{k}b_i </math>, with equality when <math>k = n </math>. If <math>\{a_i\} ...h>\sum_{i=k}^n a_i \le \sum_{i=k}^n b_i</math>, with equality when <math>k=1 </math>. An interesting consequence of this is that the finite sequence <m
    2 KB (288 words) - 22:48, 5 July 2023
  • ...function <math>f: \mathbb N \to\mathbb N</math> defined by <math>f(x) = x+1</math> is not surjective because there exists a [[natural number]] which is
    794 bytes (131 words) - 22:39, 13 May 2020
  • ...|region=International|type=Proof|difficulty=5.5 - 10|breakdown=<u>Problem 1/4</u>: 6.5<br><u>Problem 2/5</u>: 7.5-8<br><u>Problem 3/6</u>: 9.5<br><u>Pr * Gold - the top 1/12 of individual scores.
    3 KB (490 words) - 03:32, 23 July 2023
  • <cmath> \lim_{x\to \infty} \frac{\pi(x) \log x}{x} = 1 . </cmath> with <math>A(x)</math> tending to some constant number around 1.08366.
    10 KB (1,729 words) - 19:52, 21 October 2023
  • ...a_a, \lambda_b, \dotsc, \lambda_z</math> are nonnegative reals with sum of 1, then ...f{a}</math> and <math>\mathbf{b}</math>, and <math>\lambda_a = \lambda_b = 1/2</math>, this is the elementary form of the [[Cauchy-Schwarz Inequality]].
    4 KB (774 words) - 12:12, 29 October 2016
  • ...ot empty and cannot be put into bijection with any set of the form <math>\{1, 2, \ldots, n\}</math> for a [[positive integer]] <math>n</math>. <math>\sum_{i = 3}^{\infty}{(2i - 1)}</math>
    1 KB (186 words) - 23:19, 16 August 2013
  • {{asy image|<asy>draw((0,1)--(1,5)--(3,5)--(4,1)--cycle);</asy>|right|An isosceles trapezoid.}}
    577 bytes (81 words) - 10:33, 18 April 2019
  • ! scope="row" | '''Mock AMC #1''' | [http://www.artofproblemsolving.com/Forum/viewtopic.php?t=9572 1-5]
    51 KB (6,175 words) - 20:58, 6 December 2023
  • ...Y2QwOTc3NWZiYjY0LnBkZg==&rn=TWlsZG9yZiBNb2NrIEFJTUUucGRm Mildorf Mock AIME 1] ** [[Mock AIME 1 2006-2007]]
    8 KB (906 words) - 17:30, 26 April 2024
  • ...n <math>AB</math> and <math>BA</math> are matrices of sizes <math>1 \times 1</math> and <math>2 \times 2</math>, respectively.
    2 KB (301 words) - 17:46, 16 March 2012
  • ...ath>. We often drop the brackets and commas, so the permutation <math>\{2,1,3\}</math> would just be represented by <math>213</math>. ...ent objects we can choose from. For the second element, there are <math>n-1</math> objects we can choose, <math>n-2</math> for the third, and so on. I
    3 KB (422 words) - 11:01, 25 December 2020
  • ...ith <math>g(a,0)=p(a)</math>, <math>g(a,1)=q(a)</math>, and <math>g(0,b)=g(1,b)=x</math>. We call <math>g</math> a [[homotopy]]. Now define <math>\pi_1( ...>g\cdot h(a)=\begin{cases} g(2a) & 0\le a\le 1/2, \\ h(2a-1) & 1/2\le a\le 1.\end{cases}</math> One can check that this is indeed [[well-defined]].
    3 KB (479 words) - 15:35, 1 December 2015
  • <math>\frac{2^{2n}}{(2n+1)}\le{\binom{2n}{n}}\le <math>\left(\prod_{n<p\le{2n}}p\right)\ge \frac{4^{\frac n3}}{(2n+1)(2n)^{\sqrt {2n}}}</math>
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  • <cmath>\zeta (s)=\sum_{n=1}^{\infty}\frac{1}{n^s}= 1+\frac{1}{2^s}+\frac{1}{3^s}+\frac{1}{4^s}+\cdots</cmath>
    9 KB (1,547 words) - 03:04, 13 January 2021
  • ...ww.artofproblemsolving.com/Forum/viewtopic.php?p=423926#p423926 Mock USAMO 1 2006] ...http://www.artofproblemsolving.com/Forum/viewtopic.php?t=200572 Mock USAMO 1 2008]
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  • <math>1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 0, \ldots </math> This is the way in which we count in '''modulo 12'''. When we add <math>1</math> to <math>11</math>, we arrive back at <math>0</math>. The same is t
    15 KB (2,396 words) - 20:24, 21 February 2024
  • ...th> so that <math>m^2=n</math>. The first few perfect squares are <math>0, 1, 4, 9, 16, 25, 36</math>. ...th> square numbers (starting with <math>1</math>) is <math>\frac{n(n+1)(2n+1)}{6}</math>
    954 bytes (155 words) - 01:14, 29 November 2023
  • ...Equivalently, <math>f </math> is convex if for every <math> \lambda \in [0,1] </math> and every <math> x,y \in I</math>, <center><math>\lambda f(x) + (1-\lambda)f(y) \ge f\left( \lambda x + (1-\lambda) y \right) </math>.</center>
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  • Suppose that the set <math>A=\{x\in\mathbb{R}:0<x< 1\}</math> is countable. Let <math>\{\omega_1, \omega_2, \omega_3, ...\}</mat ...ath>. However, <math>\omega</math> is clearly a real number between 0 and 1, a [[contradiction]]. Thus our assumption that <math>A</math> is countable
    2 KB (403 words) - 20:53, 13 October 2019
  • ...<math>\Re(z)>0</math>, we define <cmath>\Gamma(z)=\int_0^\infty e^{-t}t^{z-1}\; dt</cmath> ...f by one. Since <math>\Gamma(1)=1</math>, we therefore have <math>\Gamma(n+1)=n!</math> for nonnegative integers <math>n</math>. But with the integral,
    840 bytes (137 words) - 22:26, 22 June 2009
  • * Subtraction: <math>a-c\equiv b-d\pmod {n}</math>. <math>\{ \ldots, -5, -2, 1, 4, 7, \ldots \}</math>
    14 KB (2,317 words) - 19:01, 29 October 2021
  • A = (0, 1); B = (1, 0);
    3 KB (499 words) - 23:41, 11 June 2022
  • ...thbb{C} \subset \mathbb{C}\cup\{\textrm{Groucho, Harpo, Chico}\} \supset \{1, 2, i, \textrm{Groucho}\}</math>
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  • * [[2006 AMC 10A Problems/Problem 1]]
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  • ...the value of the function <math>f(x)</math> at <math>x = 0</math> is <math>1</math>, the limit <math>\lim_{x\rightarrow 0} f(x)</math> is, in fact, zero ...ons <math>d_A(a,b)</math> and <math>d_B(a,b)</math> are both simply <math>|a-b|</math>. We then obtain the following definition commonly found in calculu
    7 KB (1,325 words) - 13:51, 1 June 2015
  • == Problem 1 == [[2006 AIME I Problems/Problem 1|Solution]]
    7 KB (1,173 words) - 03:31, 4 January 2023
  • ...</math> and <math> |x_k|=|x_{k-1}+3| </math> for all integers <math> k\ge 1, </math> find the minimum possible value of <math> |x_1+x_2+\cdots+x_{2006} === Solution 1 ===
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  • ...s <math>4</math> feet from the ground. In setting up the tripod, the lower 1 foot of one leg breaks off. Let <math> h </math> be the height in feet of t == Solution 1 ==
    6 KB (980 words) - 21:45, 31 March 2020
  • ...or each positive integer <math> n, </math> let <math> S_n=\sum_{k=1}^{2^{n-1}}g(2k). </math> Find the greatest integer <math> n </math> less than 1000 s == Solution 1 ==
    10 KB (1,702 words) - 00:45, 16 November 2023
  • ...e with [[edge]]-[[length]] <math> k </math> for each [[integer]] <math> k, 1 \le k \le 8. </math> A tower is to be built using all 8 cubes according to ...th>, so there are <math>2\cdot 3^6 = 1458</math> towers using blocks <math>1, 2, \ldots, 8</math>, so the answer is <math>\boxed{458}</math>.
    3 KB (436 words) - 05:40, 4 November 2022
  • ...math> c </math> are positive integers whose [[greatest common divisor]] is 1. Find <math> a^2+b^2+c^2. </math> for(i=0; i<3; i=i+1) {
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  • == Solution 1 == ...s <math>1 + \frac{1001-11}{22}=1 + \frac{990}{22}=46</math>. (We must add 1 because both endpoints are being included.) So the answer is <math>\boxed{0
    4 KB (651 words) - 18:27, 22 May 2021
  • ...1.65,-1.6), G=(0.45,-1.6), H=(3.75,-1.6), I=(2.1,0), J=(2.1,-3.2), K=(2.1,-1.6); draw(F--G--(2.1,0));
    5 KB (730 words) - 15:05, 15 January 2024
  • for(int i=0; i<4; i=i+1) { fill((2*i,0)--(2*i+1,0)--(2*i+1,6)--(2*i,6)--cycle, mediumgray);
    4 KB (709 words) - 01:50, 10 January 2022
  • == Solution 1 == ...ple, <math>.\overline{123}+.\overline{876}=.\overline{999} \Longrightarrow 1</math>.
    2 KB (237 words) - 19:14, 20 November 2023
  • == Solution 1 ==
    3 KB (439 words) - 18:24, 10 March 2015
  • ...th>'s at the right end of the decimal representation of the product <math> 1!2!3!4!\cdots99!100!. </math> Find the remainder when <math> N </math> is di ...rom <math>100</math>. Thus, our final total is <math>970 + 76 + 51 + 26 + 1 = 1124</math>, and the answer is <math>\boxed{124}</math>.
    2 KB (278 words) - 08:33, 4 November 2022
  • ...en its leftmost [[digit]] is deleted, the resulting integer is <math>\frac{1}{29}</math> of the original integer. === Solution 1 ===
    4 KB (622 words) - 03:53, 10 December 2022
  • ...et]] <math> \mathcal{A} </math> be a 90-[[element]] [[subset]] of <math> \{1,2,3,\ldots,100\}, </math> and let <math> S </math> be the sum of the elemen ...ible values of S, so the number of possible values of S is <math>4995-4095+1=901</math>.
    1 KB (189 words) - 20:05, 4 July 2013
  • ==Solution 1 (Linear Polynomials)== P(16) &= &512 + 16a + b &= 54, \hspace{20mm}&&(1) \\
    4 KB (670 words) - 13:03, 13 November 2023
  • ==Problem 1== What is the value of <cmath>\dfrac{20}{2\cdot1} - \dfrac{2+0}{2/1}?</cmath>
    12 KB (1,784 words) - 16:49, 1 April 2021
  • == Problem 1 == What is <math>( - 1)^1 + ( - 1)^2 + \cdots + ( - 1)^{2006}</math>?
    13 KB (2,058 words) - 12:36, 4 July 2023
  • * [[2006 AMC 12A Problems/Problem 1]]
    1 KB (168 words) - 21:51, 6 October 2014
  • * [[2004 AMC 12A Problems/Problem 1]]
    2 KB (186 words) - 17:35, 16 December 2019
  • ** [[2005 AMC 12A Problems/Problem 1|Problem 1]]
    2 KB (202 words) - 21:30, 6 October 2014
  • * [[2002 AMC 12A Problems/Problem 1]]
    1 KB (158 words) - 21:33, 6 October 2014
  • * [[2003 AMC 12A Problems/Problem 1]]
    1 KB (162 words) - 21:52, 6 October 2014
  • == Problem 1 == [[2006 AMC 12A Problems/Problem 1|Solution]]
    15 KB (2,223 words) - 13:43, 28 December 2020
  • == Problem 1 == (\mathrm {A}) \ 1 \qquad (\mathrm {B}) \ 2 \qquad (\mathrm {C})\ 5 \qquad (\mathrm {D}) \ 10
    13 KB (1,971 words) - 13:03, 19 February 2020
  • == Problem 1 == Alicia earns <math> 20</math> dollars per hour, of which <math>1.45\%</math> is deducted to pay local taxes. How many cents per hour of Ali
    13 KB (1,953 words) - 00:31, 26 January 2023
  • == Problem 1 == <math> \mathrm{(A) \ } 0\qquad \mathrm{(B) \ } 1\qquad \mathrm{(C) \ } 2\qquad \mathrm{(D) \ } 2003\qquad \mathrm{(E) \ } 40
    13 KB (1,955 words) - 21:06, 19 August 2023
  • == Problem 1 == [[2002 AMC 12A Problems/Problem 1|Solution]]
    12 KB (1,792 words) - 13:06, 19 February 2020
  • == Problem 1 == [[2000 AMC 12 Problems/Problem 1|Solution]]
    13 KB (1,948 words) - 12:26, 1 April 2022
  • == Problem 1 == [[2001 AMC 12 Problems/Problem 1|Solution]]
    13 KB (1,957 words) - 12:53, 24 January 2024
  • == Problem 1 == [[2002 AMC 12B Problems/Problem 1|Solution]]
    10 KB (1,547 words) - 04:20, 9 October 2022

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