First Post of 2016
by EpicSkills32, Jan 7, 2016, 7:30 AM
woah is that math I see in this post?? hey we're off to a great start already!
Today was the 2nd day of Math 1C Sequences and Series at Foothill. It's a 2 day-per-week class on Monday/Wednesday afternoons.
(oh this reminds me I forgot to post a "first impression" thing for my classes; maybe that'll come later since it's still early in the quarter)
I think what I'm gonna be doing, as time allows, is to post my notes (or relevant/significant parts) from class. Hopefully this will help me to review and digest everything.
quick thoughts on today
Ok let's see if I still remember LaTeX.
reminder to self![\[ f'(x) = \displaystyle\lim_{h\to 0} \dfrac{f(x+h)-f(x)}{h} \]](//latex.artofproblemsolving.com/9/c/0/9c0636d393138965d0bc1c37a07c5f6e95ef2e8d.png)
Definition: Given a sequence of numbers
, an expression of the form
is an infinite series.
as sequence defined by
and so on.
. . . then
Also, if
then this is known as a "sequence of partial sums." (The sequence, not the sum)
Consider
Is 0.33333333333... a rational number? NO PEEKING!
It's getting late and I should go to sleep before midnight (or preferably 11:30) cuz tomorrow there's math club, then Physics 4A, then an orthodontics checkup, then a piano lesson, then soundboard stuff.
Tomorrow I'll finish the last page (with not to much significant stuff IMO), including an interesting way of showing that
is actually convergent.
(Although I don't think it's quite rigorous)
(Sorry if there's any LaTeX errors; I'm very rusty but I spent some time on the tutorial tonight)
Today was the 2nd day of Math 1C Sequences and Series at Foothill. It's a 2 day-per-week class on Monday/Wednesday afternoons.
(oh this reminds me I forgot to post a "first impression" thing for my classes; maybe that'll come later since it's still early in the quarter)
I think what I'm gonna be doing, as time allows, is to post my notes (or relevant/significant parts) from class. Hopefully this will help me to review and digest everything.
quick thoughts on today
For a good 20 minutes (or so) of the beginning was spent trying to explain Epsilon-Delta. . . cmon goiz this is 1A stuff. . . but I guess I remember how hard it was for me to learn it. . . but still you shoulda looked it up or something when you were in 1A and now we're wasting time in 1C on this. (Khan Academy did it for me)
Totally honest, I felt like way too much of the class was spent asking stupid questions -stupid as in questions that would not exist if everyone just paid attention. People keep asking for clarification on something that was either A) already gone over at least twice or B) something on the projector already or C) something someone already (or just) asked.
But the professor is so hype so I guess that helps.
Totally honest, I felt like way too much of the class was spent asking stupid questions -stupid as in questions that would not exist if everyone just paid attention. People keep asking for clarification on something that was either A) already gone over at least twice or B) something on the projector already or C) something someone already (or just) asked.
But the professor is so hype so I guess that helps.
Ok let's see if I still remember LaTeX.
reminder to self
![\[ f'(x) = \displaystyle\lim_{h\to 0} \dfrac{f(x+h)-f(x)}{h} \]](http://latex.artofproblemsolving.com/9/c/0/9c0636d393138965d0bc1c37a07c5f6e95ef2e8d.png)
Definition: Given a sequence of numbers




. . . then

Also, if

Consider
the infinite geometric series: 
We can write this succinctly as
Now factor out a
:
Now note that the above expression can be described as a constant being multiplied to an expression involving a constant multiplied to each term. This new way of writing the series can be expressed as the following:

We now wish to generalize. Retaining the parameters for summation but replacing the constants with variables, we let
be the first constant and
be the constant by which each term in parentheses is multiplied. (r for ratio) Here is the general case:
Let's be even more general. Instead of having a boundless upper bound, let's let the upper bound be constant
.
![\[ \hookrightarrow \sum_{k=1}^n ar^{k-1} \]](//latex.artofproblemsolving.com/b/6/5/b6545da5d768aa98a3ba3d2a28fa8816dd25c6eb.png)
Now what if we look at some terms. . .

Woah that kinda looks familiar . . .
But what if we're dealing with an infinite series? What if the upper bound is infinity?
And now comes some thinking. Since we don't want to be evaluating a limit every time we deal with an infinite geometric series, we're gonna try to get rid of the limit.
We know the series will either converge or diverge. We need to figure out when and how it does which. Well let's see. The limit is based on the power n. The constant a doesn't really affect it, only the ratio r. If r is some really big positive number, then the expression clearly diverges as n gets big. The same goes if r is a really big negative number (far away from zero). What if r is really small? Well if r is a fraction, then r to the power n will go to zero, and the limit won't get infinitely big. So . . .


Note that for the latter case, the limit simplifies to

We can write this succinctly as

Now factor out a



We now wish to generalize. Retaining the parameters for summation but replacing the constants with variables, we let


![\[ \sum_{k=1}^{\infty} ar^{k-1} \]](http://latex.artofproblemsolving.com/8/3/6/836b53e51d0109f93910acad6bc36bea4215de33.png)

![\[ \hookrightarrow \sum_{k=1}^n ar^{k-1} \]](http://latex.artofproblemsolving.com/b/6/5/b6545da5d768aa98a3ba3d2a28fa8816dd25c6eb.png)
Now what if we look at some terms. . .

Woah that kinda looks familiar . . .
But what if we're dealing with an infinite series? What if the upper bound is infinity?
![\[ \sum_{k=1}^{\infty} ar^{k-1} = \lim_{n\to\infty} \dfrac{a\left(1-r^n\right)}{1-r} \]](http://latex.artofproblemsolving.com/6/a/e/6ae73ffa067de1d4eada12901f016c20e0a9db7c.png)
We know the series will either converge or diverge. We need to figure out when and how it does which. Well let's see. The limit is based on the power n. The constant a doesn't really affect it, only the ratio r. If r is some really big positive number, then the expression clearly diverges as n gets big. The same goes if r is a really big negative number (far away from zero). What if r is really small? Well if r is a fraction, then r to the power n will go to zero, and the limit won't get infinitely big. So . . .


Note that for the latter case, the limit simplifies to

Is 0.33333333333... a rational number? NO PEEKING!
You are correct if you said
The key to the definition of a rational number is the first 5 letters of the word itself. A rational number is defined as a number that can be expressed as the ratio of two nonzero integers.
Now let's have some fun with these!
Consider the rational number 4.636363636363636363636363636363636363...
We're gonna prove that it's a rational number by finding the two integers of which it is a ratio of. . . without simply knowing from inspection or multiplying by 100!
Note that we can write the number as such:
[crap it's all squished]
The two integers with ratio 4.63636363636363... are
and 
yes
The key to the definition of a rational number is the first 5 letters of the word itself. A rational number is defined as a number that can be expressed as the ratio of two nonzero integers.
Now let's have some fun with these!
Consider the rational number 4.636363636363636363636363636363636363...
We're gonna prove that it's a rational number by finding the two integers of which it is a ratio of. . . without simply knowing from inspection or multiplying by 100!
Note that we can write the number as such:

The two integers with ratio 4.63636363636363... are


It's getting late and I should go to sleep before midnight (or preferably 11:30) cuz tomorrow there's math club, then Physics 4A, then an orthodontics checkup, then a piano lesson, then soundboard stuff.
Tomorrow I'll finish the last page (with not to much significant stuff IMO), including an interesting way of showing that

(Although I don't think it's quite rigorous)
(Sorry if there's any LaTeX errors; I'm very rusty but I spent some time on the tutorial tonight)
This post has been edited 6 times. Last edited by EpicSkills32, Jan 8, 2016, 2:42 AM