Number theory

by math_explorer, Apr 21, 2011, 8:05 AM

darn now I suck at NT too

the only recent problem that I got satisfaction from:
27000001 has 4 prime factors. Find them. No calculators.

blah?
This post has been edited 1 time. Last edited by math_explorer, Aug 19, 2011, 8:19 AM

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$(3\cdot 10^2)^3 +1^3$

by Redeem, Apr 22, 2011, 3:31 AM

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(before reading the above comment)

27000001
First thing in mind: Calculate the number of zeroes, assuming 1 is counted: 6
Second thing: 27 = 3^3, 1000000 = 100^3
Third thing:
$27000001 = 300^3 + 1^3$
$= (300 + 1)(300^2 - 300 + 1)$
$= 301 \cdot 89701$

Fourth thing: Stuck

by chaotic_iak, Apr 23, 2011, 9:45 AM

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$300^2-300+1=300^2+2\cdot 300+1-900=301^2-30^2$

by Yongyi781, May 1, 2011, 5:54 PM

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