Homothety compositions

by math_explorer, Feb 5, 2012, 1:31 AM

位似 $\circ$ 旋轉 = 位似旋轉

homothety $\circ$ rotation = spiral similarity

*sigh*

Theorem. A plane transformation takes every pair of points $AB$ to a pair $A'B'$ with $\overrightarrow{A'B'} = k\overrightarrow{AB}$ for some fixed constant $k$ iff it is a homothety.

pf. (if) Similar triangles.
(only if) Send a point through the transformation, pick out the hypothetical center with ratios, and verify the rest of the plane.

zzzzzzzzz

Given two points $A, B$, any homothety on line $AB$ that does not map $A$ to $B$ can be uniquely represented as the composition of a homothety centered at $A$ followed by a homothety centered at $B$.

pf. Pick two random points $C, D$ not on line $AB$ so that the homothety we're trying to construct maps $C$ to $D$. From the fact that it doesn't map $A$ to $B$ we can deduce that $AC$ and $BD$ are not parallel, so they intersect, say at point $X$. Take the homothety centered at $A$ mapping $C$ to $X$ followed by the homothety centered at $B$ mapping $X$ to $D$. The resulting transformation is a homothety (first theorem three times), which is centered on line $AB$ by symmetry. Its center must also be on line $CD$; the intersection exists and is unique; it maps $C$ to $D$ and the ratio is also unique.

Yeah, today I'm in a hand-waving mood.

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