2006 MOSP Homework Algebra 1.4
by djmathman, Feb 15, 2013, 1:03 AM
Problem wrote:
Let
be a positive integer. Solve the system of equations
![\[\begin{cases}x_1+x_2^2+\cdots+x_n^n=n\\x_1+2x_2+\cdots+nx_n=\frac{n(n+1)}{2}\end{cases}\]](//latex.artofproblemsolving.com/5/b/9/5b906e7baa1ecba3ba036738d0e4be845d61f78f.png)
for
-tuples
of nonnegative real numbers.

![\[\begin{cases}x_1+x_2^2+\cdots+x_n^n=n\\x_1+2x_2+\cdots+nx_n=\frac{n(n+1)}{2}\end{cases}\]](http://latex.artofproblemsolving.com/5/b/9/5b906e7baa1ecba3ba036738d0e4be845d61f78f.png)
for


A little handwaving calculus doesn't hurt, right?
LEMMA: For all integers
, the polynomial
is nonnegative for all
.
Proof. First note that
, so
is a root. Taking the derivative of this function gives
. When
,
, so the overall slope of the function is negative. At
, the slope of the function is
, and when
, the slope of the function is positive. Therefore, the function can never dip below
since it is an absolute minimum along the positive real numbers. 
Subtracting the second equation from the first gives
![\[x_2^2-2x_2+x_3^3-3x_3+\cdots+x_n^n-nx_n=n-\dfrac{n(n+1)}{2}=-\dfrac{n(n-1)}{2},\]](//latex.artofproblemsolving.com/c/f/3/cf39a1e72bd03fc415b052de7e6248895520cf13.png)
so
This can be written more concisely as
From the Lemma, it is known that all the individual "terms" of this summation are nonnegative. When nonnegative expressions add up to
, each of them must be equal to
. Since it was established in the Lemma that
is a root and a relative minimum of the expression
for all
, we have that
for
. Finally, plugging our known values into the first equation gives
, so
as well. Hence
is the only solution to the system. 



Proof. First note that










Subtracting the second equation from the first gives
![\[x_2^2-2x_2+x_3^3-3x_3+\cdots+x_n^n-nx_n=n-\dfrac{n(n+1)}{2}=-\dfrac{n(n-1)}{2},\]](http://latex.artofproblemsolving.com/c/f/3/cf39a1e72bd03fc415b052de7e6248895520cf13.png)
so
\[\begin{align*}x_2^2-2x_2+x_3^3-3x_3+2+\cdots+x_n^n-nx_n+(n-1)&=-\dfrac{n(n-1)}{2}+\left[1+2+\cdots+(n-1)\right]\\&=0.\end{align*}\]
This can be written more concisely as











