How smart were those ancient geometers?

by rrusczyk, Jun 17, 2006, 3:21 PM

I was just looking through the book Journey Through Genius for some interesting bits to add to the Intro Geometry book, and I came across Heron's proof of his formula for the area of a triangle. I suppose most of my readers know this formula: given a triangle with sides of length a, b, c and semiperimeter s, its area is $\sqrt{s(s-a)(s-b)(s-c)}$. I would hope that many of my readers know how to prove this formula (but am guessing there are at least a few who don't, but should ;) ). What I'm guessing there are very few of, is readers who could prove it as Heron did. Give it a try. Keep in mind that the geometers of Heron's time did not have algebra or trig. Therefore, we're not talking about using the law of cosines, or about building right triangles and lots of algebra. We're talking about an ingenious construction, followed by a couple simple ratio manipulations.

Here is a hint.

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Journey Through Genius is a really enjoyable book to read :) I don't immmediately recall of all the details of Heron's proof, but I might just go back and try to figure out it on my own one of these days before break is over ;)

by joml88, Jun 17, 2006, 3:22 PM

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Circles, so maybe inscribe a circle in a triangle?

by 1234567890, Jun 17, 2006, 3:22 PM

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1234567890 wrote:
Circles, so maybe inscribe a circle in a triangle?

You are on the right track, but you need do a few more constructions lol...

I wonder how long did Heron take to figure out his proof lol...

by beta, Jun 17, 2006, 3:22 PM

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Journey Through Genius is a great book! And that proof of Heron's is very impressive.

by ComplexZeta, Jun 17, 2006, 3:22 PM

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Wow! What a coincidence! I just finished reading
Journey Through Genius! Great book.

by NoSoupForYou, Jun 17, 2006, 3:22 PM

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