157. Steinbart's theorem. Applications.
by Virgil Nicula, Oct 16, 2010, 7:40 AM
http://geoma29.wordpress.com/
Lemma 1. Let
be a cyclical hexagon (convex or not).
Then
.
Proof 1. Suppose that
. From the product of evident relations
obtain the required relation
. Reciprocally, suppose that the relation
is true. Denote
and
,
where
is the circumcircle of the given hexagon. Appling the direct implication which was proved above obtain
.
From the relations
and
results
. Since
obtain
. Since these triangles have same circumcircle 
(similarity ratio is equal to
) obtain
, i.e.
and
. In conclusion,
, i.e.
.
Proof 2. Suppose w.l.o.g. that the quadrilaterals
and
are convex. Denote
,
. Using the well-known relations
(in
) and
(in
) obtain that

. Using the Ptolemy's relation in the cyclical quadrilaterals
and
obtain the relations
and
. Therefore,

.
Remark. Using the previous result for the cyclical quadrilaterals
and
obtain the following chain of equivalencies :
.
Lemma 2. Let
,
be the tangent lines from
to the circle
, where
. Consider the points
,
so 
separates
,
and doesn't separate
,
. Denote
. Then exists the relation
.
Proof. Denote
. Apply the Sinus' theorem in the triangles
and
, i.e.
.
Lemma 3. Let
,
,
be three points which belong to the outside of the triangle
. Denote
.
Then
(it is the trigonometric form of the Ceva's theorem).
Steinbart's theorem. Let
be a triangle with the incircle
which touches it at
,
,
.
Consider three points
. Then
.
Proof. Using the lemma 2 obtain
.
Apply the lemma 2 to the cyclical hexagon
, i.e.
.
Thus the relation
becomes
. Using the last lemma obtain that
.
Applications.
PP1.The incircle of
touches its side
at
. Let
be the midpoint of the altitude
of triangle
. The line
meets
the incircle
of
at a point
(apart from
). Show that the circumcircle of
is tangent to the incircle of
at the point
.
Proof. Suppose w.l.o.g.
. Denote the A-exincircle
, the point
, the intersection
between the line
with the tangent
to the incircle in the point
and
. Prove easily that
,
and
. Since

obtain that
, i.e.
. The points
belong to the circle with the diameter
. Since
obtain that
. Thus
, i.e. the line
is tangent to the circumcircle of the triangle
.
PP2. Let
be the incircle in the triangle
. For all
we make the following constructions (all indices are considered modulo 3):
is the circle tangent to
which passes through the points
and
;
is the point of tangency between
and
; finally, the common
tangent in
of
and
intersects the line
in the point
. Prove that
and
.
Proof.
Lemma 1. Let

Then

Proof 1. Suppose that






where


From the relations






(similarity ratio is equal to






Proof 2. Suppose w.l.o.g. that the quadrilaterals























Remark. Using the previous result for the cyclical quadrilaterals



Lemma 2. Let








separates






Proof. Denote




Lemma 3. Let





Then

Steinbart's theorem. Let





Consider three points


Proof. Using the lemma 2 obtain




Apply the lemma 2 to the cyclical hexagon


Thus the relation




Applications.
PP1.The incircle of







the incircle







Proof. Suppose w.l.o.g.





to the incircle in the point





















PP2. Let










tangent in







Proof.
This post has been edited 50 times. Last edited by Virgil Nicula, Dec 1, 2015, 10:12 AM