279. O.M. Holland , O.M. Ireland 1988 and TST USA 2000, etc.
by Virgil Nicula, May 21, 2011, 2:19 AM
PP1 (Holland). Let
be a triangle with
. Denote
and the symmetrical
of
w.r.t.
. Prove that
.
Proof 1. Denote the symmetrical point
of the point
w.r.t.
and
. Since
is
-right angled and
results that the median
from
is homologously in similitude with the median
from
, i.e.
is cyclic
.
Proof 2. Denote the midpoint
of
. Observe that
is
-altitude in
the point
is the orthocenter of
.
Proof 3. Denote the points
and
so that
. Observe that
is a parallelogram 
, i.e.
is the orthocenter of
.
Proof 4. Denote
. Observe that
, i.e.
. From the well-known relation 
, i.e.
. Since
from
and
obtain that
, i.e.
.
An easy extension. Let
be an
-right angled triangle. Denote the point
for which
.
Consider the points
and
so that
and
. Prove that
.
Proof 1. Denote
. Observe that
. From the well-known relation 
obtain that
. Since
obtain that
. From the relations
and 
obtain that
, what is truly.
Proof 2. Let
and
for which
and
. So
.
Denote
. Then
. In
we have
and
.
PP2 (easy - Holland). Let
be an
-isosceles triangle. Consider two points
and 
so that
. Prove that the circumcenter of
belongs to the circumcircle of
.
Proof. Denote the circumcircle
of
. Observe that 
, i.e. the circumcenter
of the triangle
belongs to the circumcircle of
.
PP3 (Ireland - 1988). Let
be a point of the small arc
in the circumircle of the square
. Prove that
.
Proof 1 (metric). Apply Ptolemy's theorem to
.
Proof 2 (trigonometric). Denote
. Observe that
(degrees) and the required relation
is equivalently with the trigonometrical relation
. Since 
prove easily that
and
, i.e.
.
An easy extension. Let
be a point of the small arc
in the circumircle of the isosceles trapezoid
with
and
. Prove that
.
Proof (metric). Apply Ptolemy's theorem to
.
A similar problem. Let
be an
-isosceles triangle with the circumcircle
. Consider two mobile points 
so that the sideline
separates
,
and doesn't separate
,
. Prove that the ratio
is constant.
Proof. Denote
so that
is a diameter of
. Construct
so that
,
. Apply the Ptolemy's theorem
to the quadrilaterals
. Observe that the relation

. Thus, 
and
(constant).
PP4 - Turkey TST 2011. Let
with incenter
and circumcircle
. Denote diameter
of
and
. Show that
.
Proof. Observe that
and
. Apply the Pythagoras' relation in the mentioned triangles :




In conclusion,
.
PP5 - USA TST 2000. Let
be a cyclic quadrilateral and let
and
be the feet of perpendiculars from the intersection of diagonals
and
to
and
respectively. Prove that
is perpendicular to the line through the midpoints of
and
.
Lemma. Construct outside of
the right triangles
. Denote the midpoint
of
, Prove that
.
Proof 1 (synthetic)
Proof 2 (metric)
Proof. Denote
and the midpoints
,
of
,
respectively. Apply above lemma to
and its exterior right
,
.
Obtain
. Apply again above lemma to
and its exterior right
,
. Obtain
.In conclusion,
.
Another proof. Let
,
be the midpoints of
,
respectively. Let
be the intersection of diagonals. Let
,
be the reflections of
over
, 
respectively. We know that
and
are directly similar and are kites. Then the midpoints of the lines connecting corresponding points of the two
similar figures forms a figure similar to the original, i.e.
is similar to both
and
. Therefore
is a kite and
.
PP6 - Polosh & Costa Rica 2006. Let
be an acute triangle. Its incircle
touches it at the points
,
,
. Denote:
the centroid
of the triangle
;
the A-exincircle
, the B-exincircle
, the C-exincircle
;
the Nagel's point
;
,
,
;
the points
,
,
;
the reflections
,
,
of the points
,
,
with respect to the point
.
Lemma 1.
.
Proof.

.
Remark.
and
. Therefore,
.
Lemma 2.
;
;
and
a.s.o.
Proof. Apply the Stewart's relation for the Nagel-ray
in the triangle
and obtain the relation
.
Apply the van Aubel's relation
and obtain the relation
.

, i.e. the relations
.
Remark.
.
An equivalent and complete enunciation of the proposed problem. Let
be an acute triangle for which
. Then
are cyclically
and in this case
belong to
the circle
, where the point
is the second intersection between the line
and the circumcircle of the triangle
.
Proof (indication). The points
are cyclically
a.s.o.
Example.
,
,
. Remark.

.
PP7 - 32nd BMO 1996. Let
for which
.
Proof.
.
PP8 - 8th China Southeast MO. In
, for an interior
denote
and 
. Construct similarly the points
and
. Prove that
.
Proof. Denote
,
and
. Suppose w.l.o.g.
. Obtain that
and
. Apply Menelaus' teorem
to transversal
. Analogously
and
. Hence
.
PP9 (Iran TST 2007, Day 2). Let
be the incircle of the triangle
. Let
and
be two points such that
and
is tangent to the circle
. The
lines
,
touch the circle
at
,
respectively. Denote the middlepoint
of
and
. Prove that the line
is tangent to the circle
(Ali Khezeli)
Proof. Denote the intersection
and the middlepoints
,
of the segments
,
respectively. Observe that
,
. From the well-known properties
and
obtain immediatelly that
, i.e.
and the line
is tangent to the circle
because the lines
,
are symmetrically w.r.t the line
.
Proof of the property - the point S belongs to the line IV.
Proof of the property - the lines TI and AD are perpendicularly.







Proof 1. Denote the symmetrical point













Proof 2. Denote the midpoint

![$[AD]$](http://latex.artofproblemsolving.com/0/f/3/0f3e4c424371b27673db323ced8ef0777940c0d4.png)








Proof 3. Denote the points










Proof 4. Denote












An easy extension. Let




Consider the points





Proof 1. Denote



obtain that





obtain that





Proof 2. Let







Denote







PP2 (easy - Holland). Let




so that



Proof. Denote the circumcircle







PP3 (Ireland - 1988). Let




Proof 1 (metric). Apply Ptolemy's theorem to



Proof 2 (trigonometric). Denote






prove easily that



An easy extension. Let






Proof (metric). Apply Ptolemy's theorem to



A similar problem. Let




so that the sideline





![$\frac {[BPCQ]}{AQ^2-AP^2}$](http://latex.artofproblemsolving.com/e/4/0/e409021322e11cbef8a3f86d4f77f8bfad9f45c4.png)
Proof. Denote

![$[AA']$](http://latex.artofproblemsolving.com/f/8/3/f83bdc8e170d3bc867097c603fa03cf6edefbb4b.png)




to the quadrilaterals






and
![$\frac {[BPCQ]}{AQ^2-AP^2}=$](http://latex.artofproblemsolving.com/8/8/d/88df5a44f4fd8f01370ea197fb0e0367d4626e3d.png)
![$\frac {[BPC]+[BQC]}{AQ^2-AP^2}=$](http://latex.artofproblemsolving.com/e/c/4/ec49e99e7072454675fbd42d03ab13db7a020f96.png)


PP4 - Turkey TST 2011. Let



![$[AD]$](http://latex.artofproblemsolving.com/0/f/3/0f3e4c424371b27673db323ced8ef0777940c0d4.png)



Proof. Observe that











In conclusion,

PP5 - USA TST 2000. Let










Lemma. Construct outside of



![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)

Proof 1 (synthetic)
Denote the midpoints
,
of the sides
,
respectively. Since
.


![$[AB]$](http://latex.artofproblemsolving.com/a/d/a/ada6f54288b7a2cdd299eba0055f8c8d19916b4b.png)
![$[AC]$](http://latex.artofproblemsolving.com/0/9/3/0936990e6625d65357ca51006c08c9fe3e04ba0c.png)


Proof 2 (metric)
Denote
. Observe that
,
and
. Apply the generalized Pytagoras' theorem in :
.
Thus,


, what is truly.





Thus,




![$2\left(b^2-c^2\right)\cdot\cos\phi =\left[\left(a^2+b^2-c^2\right)-\left(a^2+c^2-b^2\right)\right]\cdot\cos\phi$](http://latex.artofproblemsolving.com/f/d/2/fd2dc00b4463529c862b9f91654289cc59cf47b2.png)
Proof. Denote



![$[AD]$](http://latex.artofproblemsolving.com/0/f/3/0f3e4c424371b27673db323ced8ef0777940c0d4.png)
![$[CD]$](http://latex.artofproblemsolving.com/e/7/0/e70960e9e5738a46ad23f794e796ef3cb4ad7e2c.png)



Obtain






Another proof. Let










respectively. We know that


similar figures forms a figure similar to the original, i.e.





PP6 - Polosh & Costa Rica 2006. Let





























Lemma 1.

Proof.





![$\frac 19\left\{\left[2\left(a^2+c^2\right)-b^2\right]-\left[2\left(a^2+b^2\right)-c^2\right]\right\}$](http://latex.artofproblemsolving.com/3/2/9/329f57c95e21b647aae442d05502ce94fa6aeac4.png)




Remark.





Lemma 2.





Proof. Apply the Stewart's relation for the Nagel-ray



Apply the van Aubel's relation











Remark.

An equivalent and complete enunciation of the proposed problem. Let










the circle




Proof (indication). The points



Example.










PP7 - 32nd BMO 1996. Let


Proof.



![$4\sqrt[4]{s_4}\ge 12=s_1\ge 4\sqrt[4]{s_4}\implies$](http://latex.artofproblemsolving.com/6/e/7/6e73ba959481dcc46e127b718877a12a90f20b96.png)
![$\frac {s_1}{4}=\sqrt[4]{s_4}\implies$](http://latex.artofproblemsolving.com/d/3/a/d3a3bd98ce762ccb71efdb5e09ec192ff6fdf3f8.png)

PP8 - 8th China Southeast MO. In








Proof. Denote






to transversal





PP9 (Iran TST 2007, Day 2). Let







lines






![$[PQ]$](http://latex.artofproblemsolving.com/2/1/c/21ca08816cf8b23ddf756ce9ae098ad327f2443d.png)



Proof. Denote the intersection



![$[AD]$](http://latex.artofproblemsolving.com/0/f/3/0f3e4c424371b27673db323ced8ef0777940c0d4.png)
![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)











Proof of the property - the point S belongs to the line IV.
Suppose w.l.o.g.
. Denote the intersection
. Prove easily that
,
,
. Apply the Menelaus' theorem to the transversal
and the triangle
, i.e.
.










Proof of the property - the lines TI and AD are perpendicularly.
The line
is the polar
of the point
w.r.t. the circle
and the point
the point
belongs to the polar
of the point
w.r.t. the circle
and
The polar of the point
is
.
Remark. Otherwise prove easily that
.
















Remark. Otherwise prove easily that

This post has been edited 110 times. Last edited by Virgil Nicula, Nov 22, 2015, 6:55 AM