252. OI=f(A,R) in certain conditions.

by Virgil Nicula, Mar 12, 2011, 8:12 AM

Proposed problem. Prove that $\sin\frac A2=\lambda\ \iff\ OI=R\cdot\sqrt {(2\lambda -1)^2+8\lambda\sin^2\frac {B-C}{4}}$ .

Proof. Observe that $\sin\frac A2=\lambda\iff \cos A=1-2\lambda^2$ . Since $\sum\cos A=1+\frac rR$ obtain that $\sin\frac A2=\lambda\iff -2\lambda^2+\cos B+\cos C=\frac rR\iff$

$2\lambda\cdot\cos\frac {B-C}{2}=2\lambda^2+\frac rR\iff$ $2\lambda\cdot \left(1-2\sin^2\frac {B-C}{4}\right)=2\lambda^2+\frac rR\iff$ $4\lambda R^2\left(1-2\sin^2\frac {B-C}{4}\right)=4\lambda^2R^2+2Rr$ .

Since $OI^2=R^2-2Rr$ results $OI^2=R^2+4\lambda^2R^2-4\lambda R^2+8\lambda R^2\sin^2\frac {B-C}{4}\iff$ $OI=R\cdot\sqrt {(2\lambda -1)^2+8\lambda\sin^2\frac {B-C}{4}}$ .

Remark. $\left\|\begin{array}{cccc}
\blacktriangleright & \frac {2r}{R}\le 4\sin\frac A2\left(1-\sin\frac A2\right)\le 1 & \mathrm{with\ left\ equality\ iff} & B=C\\\\
\blacktriangleright & \frac {2r}{R}\le 1-8\sin\frac A2\sin^2\frac {B-C}{4}\le 1 & \mathrm{with\ left\ equality\ iff} & A=60^{\circ}\end{array}\right\|$ .

Particular case.

$\blacktriangleright\ A=60^{\circ}\ \iff\ OI=2R\cdot \sin\frac {|B-C|}{4}$ . Observe that $\left\|\begin{array}{ccc}
OI=b & \iff & B=20^{\circ}\\\
OI=BH & \iff & B=80^{\circ}\\\
OI=2\cdot DF & \iff & B=12^{\circ}\end{array}\right\|$ , where $D=\mathrm{pr}_{BC}A$ and $F=\mathrm{pr}_{AB}C$ .

$\blacktriangleright\ OI\parallel BC\iff$ $R\cos A=r\iff$ $\cos B+\cos C=1\iff$ $2\sin\frac A2\cos\frac {B-C}{2}=1\iff$ $1-2\sin^2\frac {B-C}{4}=\cos\frac {B-C}{2}=\frac {1}{2\lambda}\iff$

$\sin^2\frac {B-C}{4}=$ $\frac {2\lambda -1}{4\lambda}\iff$ $OI=R\cdot \sqrt {4\lambda^2-1}\iff$ $\frac {OI}{BC}=\frac {\sqrt {4\lambda^2-1}}{2\sin A}\iff$ $\frac {OI}{BC}=\frac {\sqrt {4\lambda^2-1}}{4\lambda\sqrt{1-\lambda^2}}$ , where $\lambda=\sin\frac A2$ .
This post has been edited 15 times. Last edited by Virgil Nicula, Nov 22, 2015, 11:05 AM

Comment

0 Comments

Own problems or extensions/generalizations of some problems which was posted here.

avatar

Virgil Nicula
Archives
+ October 2017
+ September 2017
+ December 2016
+ October 2016
+ February 2016
+ September 2013
+ October 2010
+ September 2010
Shouts
Submit
  • orzzzzzzzzz

    by mathMagicOPS, Jan 9, 2025, 3:40 AM

  • this css is sus

    by ihatemath123, Aug 14, 2024, 1:53 AM

  • 391345 views moment

    by ryanbear, May 9, 2023, 6:10 AM

  • We need virgil nicula to return to aops, this blog is top 10 all time.

    by OlympusHero, Sep 14, 2022, 4:44 AM

  • :omighty: blog

    by tigerzhang, Aug 1, 2021, 12:02 AM

  • Amazing blog.

    by OlympusHero, May 13, 2021, 10:23 PM

  • the visits tho

    by GoogleNebula, Apr 14, 2021, 5:25 AM

  • Bro this blog is ripped

    by samrocksnature, Apr 14, 2021, 5:16 AM

  • Holy- Darn this is good. shame it's inactive now

    by the_mathmagician, Jan 17, 2021, 7:43 PM

  • godly blog. opopop

    by OlympusHero, Dec 30, 2020, 6:08 PM

  • long blog

    by MrMustache, Nov 11, 2020, 4:52 PM

  • 372554 views!

    by mrmath0720, Sep 28, 2020, 1:11 AM

  • wow... i am lost.

    369302 views!

    -piphi

    by piphi, Jun 10, 2020, 11:44 PM

  • That was a lot! But, really good solutions and format! Nice blog!!!! :)

    by CSPAL, May 27, 2020, 4:17 PM

  • impressive :D
    awesome. 358,000 visits?????

    by OlympusHero, May 14, 2020, 8:43 PM

72 shouts
Tags
About Owner
  • Posts: 7054
  • Joined: Jun 22, 2005
Blog Stats
  • Blog created: Apr 20, 2010
  • Total entries: 456
  • Total visits: 404396
  • Total comments: 37
Search Blog
a