207. Some interesting problems of Toshio Seimiya, Japan.
by Virgil Nicula, Jan 11, 2011, 10:06 AM
PP1 (T.S.). Let
be a convex quadrilateral. Denote
and the midpoints
,
,
of
,
,
respectively. Prove that
.
Proof.
PP2 (T.S.). Let
be a convex quadrilateral. Denote
, the midpoints
,
of
,
respectively
and the point
for which
. Prove that
is a trapezoid.
Proof.
PP3 (T.S). Let
be an acute triangle. Construct outside of it the equilateral triangles
,
. Denote the intersections
,
and
. Prove that
.
Proof.
PP4 (own). In the convex quadrilateral
denote
. Prove that
and
have same centroid iff
.
Proof.
PP5 (own). In convex
denote
and the midpoints
,
,
,
of
,
,
,
respectively. Denote
. Prove that
.
Proof.
PP6. Let
with incircle
Prove that
so that
is tangent to
exists the relation 





![$[BD]$](http://latex.artofproblemsolving.com/3/2/6/3261e689901bce018ecdef47b9bc60a78ead3746.png)
![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)
![$[AC]$](http://latex.artofproblemsolving.com/0/9/3/0936990e6625d65357ca51006c08c9fe3e04ba0c.png)
![$AL\cap IM\cap DN\ne\emptyset\iff AD\parallel BC\ \vee\ [ABCD]=2\cdot [BIC]$](http://latex.artofproblemsolving.com/8/5/c/85c56db50903935f653bcd8aa22fdfc02512084f.png)
Proof.
Proof (vectorial). Choose the origin
of the vectorial system and denote
for any
. Therefore, 
. The lines
,
,
are concurrently
exist three real numbers
,
and
so that

. From elimination of the parameters
,
,
in the last two relations obtain the relation
. Appear two cases :
.
.


























![$[CID]=[AIB] \implies$](http://latex.artofproblemsolving.com/2/5/4/25498ae942c1bd2070f35e577f91932753caa429.png)
![$ [ACD]=[ABD]$](http://latex.artofproblemsolving.com/9/8/9/9891261e734c993d7c18c431756696fcf98f6ff0.png)



![$\frac {[ABCD]}{ [AIB]}=2\cdot \frac {[BIC]}{[AIB]}\implies$](http://latex.artofproblemsolving.com/8/1/9/819ff992a1bb50816ad323d8f68fefc3e1b77d58.png)
![$[ABCD]=2\cdot [BIC]$](http://latex.artofproblemsolving.com/5/6/3/5632fa7041c19b24569b4b895d90ce0e16589b6c.png)
PP2 (T.S.). Let




![$[AB]$](http://latex.artofproblemsolving.com/a/d/a/ada6f54288b7a2cdd299eba0055f8c8d19916b4b.png)
![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)
and the point



Proof.
Proof (vectorial). Choose the origin
of the vectorial system and denote
for any
. Therefore, 
. The lines
,
,
are concurrently
exist three real numbers
,
and
so that

. From elimination of the parameters
,
,
in the last two relations obtain the relation

ABCD is a trapezoid.

























![$\iff [CID]=[AIB]\iff [ABD]=[ACD]\iff$](http://latex.artofproblemsolving.com/c/f/6/cf6c2703a9ef982e606d46d27306d7f8b3e49365.png)


PP3 (T.S). Let






![$[AFPG]=[BPC]\ \iff\ A=60^{\circ}$](http://latex.artofproblemsolving.com/c/c/f/ccfece1622b8f636b7d0bc0650a17dae9e8463e2.png)
Proof.
Proof.
.
Denote
and
. Observe that
because
. From the relations 
and
obtain

. Since
obtain
that
.
![$[AFPG]=[BPC]\iff $](http://latex.artofproblemsolving.com/0/c/b/0cbcf235b01ff0cc4e016391d9ad79a09d226a2d.png)
![$[ABG]=[BCF]\iff$](http://latex.artofproblemsolving.com/b/2/0/b2067a5099bbcd56745e15b9284ec4f4fec790c1.png)





Denote





and

![$[AFPG]=[BPC]\iff$](http://latex.artofproblemsolving.com/0/0/4/00490924c7e3810d9062ad7df3cacd8f50538716.png)




that








PP4 (own). In the convex quadrilateral





Proof.
Proof (vectorial). Choose the origin
of the vectorial system and denote
for any
. Therefore,
.
Therefore,
exist the real numbers
and
so that

. Hence
and
have same centroid 
. From the elimination of
,
between the relations
,
obtain that

and
and
. Observe that
.





Therefore,































PP5 (own). In convex






![$[AB]$](http://latex.artofproblemsolving.com/a/d/a/ada6f54288b7a2cdd299eba0055f8c8d19916b4b.png)
![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)
![$[CD]$](http://latex.artofproblemsolving.com/e/7/0/e70960e9e5738a46ad23f794e796ef3cb4ad7e2c.png)
![$[DA]$](http://latex.artofproblemsolving.com/7/b/e/7be1ee9448ef63ac6f1f6b8dd6982c30bad9bb31.png)


Proof.
Proof (vectorial). Choose the origin
of the vectorial system and denote
for any
. Therefore,
.
Thus,
and exist the real numbers
,
,
,
so that

.
Denote the point
for which
and
. Thus, exist
so that
,
i.e.
, where

and


. Since
doesn't a trapezoid (exist the points
,
) obtain that
and
.





Thus,












Denote the point





i.e.






















PP6. Let






This post has been edited 59 times. Last edited by Virgil Nicula, Dec 10, 2017, 9:39 AM