423. Geometry problems.
by Virgil Nicula, Mar 28, 2015, 11:49 PM
Lemma 1 (well known). Let the triangle
. Prove that for any point
there is the relation 
Proof.

Lemma 2 (well known). Let
be a triangle and the points
,
,
where
. Prove that
.
Proof. Denote
. Therefore,
, i.e. the required relation.
Lemma 3. Let a convex
with
Prove that for any
and
so that
there is the relation
Proof. Denote
Apply the lemma

PP3. Let a convex pentagon
where
,
,
and
. Prove that
.
Proof. Let
and
. Thus,

Therefore,

from the relation (*). In conclusion, 
i.e.
From the relation
get
i.e. 
PP4 (Cr.Tello). Let
and equilateral
so that
. Let:
,
;
,
. Prove that
.
Proof. Prove easily that
, where
. Let
.
In conclusion,
.
PP5 (R.A). Let
with
,
,
and
. Prove that
.
Proof. I"ll use the well known identities
and
in any
. Thus,

Thus,

I"ll prove the first required relation
. Indeed,
.
PP6 (R.A). Let
with
and
. Prove that 
Proof. Denote the incircle
and observe that
Remark that the circumradius of
has
the length
and
is the circumcircle of
. In conclusion, from the relations
obtain that 
and
.
I"ll prove the first relation
. Indeed,
.
PP7 (Miguel Ochoa). Let
with
and
Prove that 
Proof. Apply

Particular case. If the point
is the incenter of
and
then 
PP8 (Ruben Dario). For an interior point
of
let its cevian
, where
,
and
. For an
interior
of
let its cevian
, where
,
and
. Prove that
.
Proof. Denote
and apply the upper lemma
in
for the points


. Apply the Ceva's theorem to the mentioned points and suitable triangles 

PP9 (Ruben Dario). Let
be a rectangle where
and
.
Prove that
Proof. Denote
and apply the theorem of Cathetus
. Thus,
is cyclically 
and from the theorem of Cathetus in
obtain that
. Therefore,

. In conclusion,

Apply the theorem of Cathetus in
, i.e.
and the equivalence
.
Extension. Let a parallelogram
with
and the points
so that
Prove that
Proof (analytic). Let
. There is
so that
. Thus,
Therefore, 
Hence the equations
and
have at least a common root, i.e.
.
Denote
. Thus, the previous relation becomes

Observe that
.
PP10 (Miguel Ochoa Sanchez). Let
be a square with the points
and
. Prove that

Proof. Denote
and
, where
Thus, 
is cyclically


Remark.
is cyclic
and
is cyclic, where 
An easy extension. Let
be a rectangle with
and
Prove that

Proof. Denote
, where
Thus,
is cyclically 

PP11 (Ruben Dario). Let the circle
with
so that
and
doesn't separate
and
.
Denote
,
and
so that
. Prove that 
Proof 1 (Juan Daniel Valdivia Fuentes). Denote
and observe that
Apply the Menelaus' theorem to the transversal
over
the division
is harmonically. Hence

Therefore,
and
More exactly, 
Proof 2 (Ruben Dario). Nice proof ! Denote the midpoints
,
of
,
respectively, i.e.
and
. Therefore,

With other words. Let
Thus,

PP12 (Ruben Dario). Let
with incircle
Denote
. Prove that 
Proof 1.

Proof 2. Denote
and apply the theorem of Sines in the mentioned triangles 



In conclusion, 
PP13 (Miguel Ochoa Sanchez). Let
with the incircle
Let
and
Prove that 
Proof. Let
. Thus,
and

Apply the Pyhagoras' theorem to 




Hence the relations

The Ptolemy's theorem for
, i.e.

Remark. Denote
Define
Thus,


See here the Leo Giugiuc's proof.
PP14 (Ruben Auqui). Let an equilateral
and
so that
. Prove that
.
Proof 1.
,
,
the generalized Pythagoras' theorem
,
i.e.
. Let
and apply
for any
to
of
.
Proof 2. Let
. So
and
. I"ll use the well-known relation (get it easily with Stewart's)
, i.e. 
. Let
. Thus,
. So 
and
.
Proof 3. Let
. I"ll use the well-known relation
, i.e.

, i.e.
is the midpoint of
. So
.
PP15 (Miguel Ochoa Sanchez). Let
be a square what is inscribed in the circle
. Prove that
.
Proof 1. Suppose w.l.o.g. that
belongs to the small arc
. Let
and
. Thus,
and from the right
and
obtain that
, i.e.
and
. Thus,

. So
.
Proof 2. Let
, where
. Prove easily
, where
. So, 

.
PP16 (Miguel Ochoa Sanchez). Let
with incircle
such that
and
. Prove that
, where
is length of circumradius
Proof. I"ll use the well-known identity (can prove it easily !)
, where
. Thus,
and 
. In conclusion,
is a
-right triangle
.
Remark. Let
with the incircle
, the
-excircle
and
. Is well-known that
, i.e.
and
(from the power of
w.r.t. the circumcircle). Thus,

.
PP17 (Miguel Ochoa Sanchez). Let
and a point
which belongs to the small arc
. Prove that
, where
is the area of
.
Proof. Apply the Ptolemy's theorem
and the generalized Pytagoras' theorem
. Prove easily that the relations 


.
Remark.
.
PP18 (Miguel Ochoa Sanchez). Let
with the
-excircle
and
. Prove that
.
Proof.Is well-known that
. Apply the Ceva's theorem to the point
and 
. Apply the Menelaus' theorem to the transversals

.
PP19 (Gustavo Jimmy Garcia Paytan). Let
with the incircle
and the points
so that the lines
are tangent to
. Denote
the lengths
of the inradii for the triangles
,
and
respectively. Prove that
.
Proof. Observe that

and

.
Observe that
. In conclusion, the required relation is truly.
PP20 (Miguel O. Sanchez). Let an
-isosceles
and its interior
so that
. Let
. Prove that the ray
is the
-symmedian in
.
Proof 1 (trigonometric). Denote
and
. Apply the trigonometric form
of the Ceva's theorem

. Thus,
.
Proof 2 (trigonometric). Denote
and
. Apply the Ceva's theorem
to the point
and
. Observe that
. I"ll use an well-known the relations
.
Proof 3 (metric). Prove easily that
and
are tangent to the circumcircle
of
. Denote
. Hence
.
Therefore,
.
PP21 (Ruben Dario). Let an
-isosceles
with the incircle
which touches given triangle at
,
and
. Prove that for any
and
so that
is tangent to
there are the relations
.
Proof. Suppose w.l.o.g.
and denote
, where
. Prove easily that
. Thus 


, what is truly.






Proof.
![$\frac {DB}{DC}=\frac {[ABD]}{[ACD]}=\frac {AB\cdot AD\cdot\sin\widehat{DAB}}{AC\cdot AD\cdot\sin\widehat{DAC}}\implies$](http://latex.artofproblemsolving.com/7/8/6/786603616d3abc64bf7db117256ad0919a1f84d6.png)

Lemma 2 (well known). Let






Proof. Denote




Lemma 3. Let a convex






Proof. Denote





PP3. Let a convex pentagon






Proof. Let






Therefore,












PP4 (Cr.Tello). Let








Proof. Prove easily that




In conclusion,





PP5 (R.A). Let






Proof. I"ll use the well known identities

















PP6 (R.A). Let




Proof. Denote the incircle



the length













I"ll prove the first relation





PP7 (Miguel Ochoa). Let




Proof. Apply



Particular case. If the point




PP8 (Ruben Dario). For an interior point






interior







Proof. Denote















PP9 (Ruben Dario). Let



Prove that

Proof. Denote
















Apply the theorem of Cathetus in






Extension. Let a parallelogram





Proof (analytic). Let


![$\left\{\begin{array}{c}
F(a\lambda +b,c)\\\\
E[(a+b)\lambda ,c\lambda]\\\\
G\left(\frac {a+b}{2-\lambda},\frac c{2-\lambda}\right)\end{array}\right\|$](http://latex.artofproblemsolving.com/f/9/e/f9eec9a0dc6f30a5c0349edc96338e3c6e2ae3e7.png)














![$\left[\left(a^2+2ab\right)-\left(b^2+c^2\right)\right]^2=-\left(a^2+2ab\right)\cdot\left[3\left(b^2+c^2\right)-2\left(a^2+2ab\right)\right]$](http://latex.artofproblemsolving.com/9/f/b/9fbfb91d66cee547456ca126de2acdf6dfb22e93.png)
Denote




Observe that





PP10 (Miguel Ochoa Sanchez). Let





Proof. Denote

















Remark.






An easy extension. Let





Proof. Denote











PP11 (Ruben Dario). Let the circle






Denote





Proof 1 (Juan Daniel Valdivia Fuentes). Denote










Therefore,









Proof 2 (Ruben Dario). Nice proof ! Denote the midpoints


![$[MA]$](http://latex.artofproblemsolving.com/d/d/f/ddf91ec100609c83be5c154de4e74c7649687ba6.png)
![$[MD]$](http://latex.artofproblemsolving.com/9/7/8/97872638fc3f0f502d3ea893f138d450be76d57e.png)







With other words. Let




PP12 (Ruben Dario). Let




Proof 1.



Proof 2. Denote
























PP13 (Miguel Ochoa Sanchez). Let





Proof. Let




















Hence the relations







Remark. Denote







![$\frac {uv}w=\frac {u+v+w}3\ge \sqrt[3]{uvw}$](http://latex.artofproblemsolving.com/4/b/f/4bfa7e8c85ad4e7cf8852eef76c141b203f579e4.png)


See here the Leo Giugiuc's proof.
PP14 (Ruben Auqui). Let an equilateral




Proof 1.





i.e.







Proof 2. Let











and






Proof 3. Let






![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)




PP15 (Miguel Ochoa Sanchez). Let



Proof 1. Suppose w.l.o.g. that

![$\overarc[]{BC}$](http://latex.artofproblemsolving.com/a/1/6/a1630e6627fd1370ac41004e3844e8c72c17e345.png)












![$\sum a^4=\left(\sum a^2\right)^2-2\left[a^2c^2+b^2d^2+\left(a^2+c^2\right)\left(b^2+d^2\right)\right]=$](http://latex.artofproblemsolving.com/8/1/b/81b28a82d942d7b0e638f4cecefdfaeb3fde86c5.png)


Proof 2. Let














![$\cdot \left[4-\left(\sin^22x+\cos^22x\right)\right]=\frac 32\implies$](http://latex.artofproblemsolving.com/2/5/8/2581f0e6cf408b23c22fb461d52fea0c34b128e0.png)


PP16 (Miguel Ochoa Sanchez). Let






Proof. I"ll use the well-known identity (can prove it easily !)


































PP17 (Miguel Ochoa Sanchez). Let


![$\overarc[]{AC}$](http://latex.artofproblemsolving.com/3/2/1/321d1e83d833ec725a63feb78320f1930d4eb295.png)



Proof. Apply the Ptolemy's theorem







![$\sin 2B\left[(ax+cz)^2-2acxz\right]\ \stackrel{(*)}{=}$](http://latex.artofproblemsolving.com/e/5/8/e585f13e19fbac6ac66d3f604de43d0d55985b30.png)




Remark.






PP18 (Miguel Ochoa Sanchez). Let





Proof.Is well-known that









PP19 (Gustavo Jimmy Garcia Paytan). Let





the lengths





Proof. Observe that
















Observe that


PP20 (Miguel O. Sanchez). Let an








Proof 1 (trigonometric). Denote


of the Ceva's theorem








Proof 2 (trigonometric). Denote


to the point









Proof 3 (metric). Prove easily that






Therefore,




PP21 (Ruben Dario). Let an











Proof. Suppose w.l.o.g.

















![$\frac {\sin \phi}{\cos 2\phi}\cdot\left[\frac {\sin(2\phi -u)}{\cos (\phi -u)}+\frac{\sin(2\phi -v)}{\cos (\phi -v)}\right]=$](http://latex.artofproblemsolving.com/8/e/c/8ecad6fec2973a3dfb22ac89390142ba48e81581.png)



![$\frac {\sin \phi}{\cos 2\phi}\cdot\frac {2\sin\phi [1+\cos (u-v)]}{1+\cos (u-v)}=$](http://latex.artofproblemsolving.com/2/d/3/2d307dddc35fb0c46b574074d79af2da8e710341.png)




This post has been edited 437 times. Last edited by Virgil Nicula, Feb 11, 2018, 3:01 PM