433. Some properties of remarkable lines in a triangle II.
by Virgil Nicula, Nov 16, 2015, 2:27 PM
P1. Let
, the midpoint
of
,
and intersection
of tangent lines at
,
to circle with diameter
. Prove that
.
Proof 1 (synthetical). Let
be a point for which
and
. Denote
. Observe that

and
, i.e.
is an harmonic cyclic quadrilateral.
From an well-known property obtain that
- the bisector of the side
, i.e.
. I was inspired by phuongtheong. Thank you.
Proof 2. Let
, the circle
with the diameter
and the intersections
,
of the perpendicular bisector of the side
with the tangent lines to t
at
, 
respectively. We observe that
and
, i.e.
. From the Sinus' theorem applied in
,
results 
and
. Therefore, the point
belongs to the perpendicular bisector of the side

, what is truly, from the relation
and the identity posted here
Remark. Prove easily that
,
. Since
obtain that
.
Otherwise.

, where
is the intersection of the tangent lines at
,
to the circumcirle of
.
P2. Let
be an
-isosceles triangle. For
denote second intersection
of the line
with the circumcircle of
. Prove that
,
.
Proof 1.
,
.
Proof 2 (trigonometric). Denote
. Observe that
,
and
. Thus, 
, what is truly.
Extension. Let
and for
denote the second intersection
of the line
with the circumcircle of
. Prove that
.
Proof.
.
P3. Let
and the midpoints
,
of
,
respectively and the intersections
,
of the
-symmedian with
,
respectively. Prove that
.
Proof 1 (metric). Denote
. It's well-known that
. Apply the Menelaus' theorem to the transversals:

is cyclic
.
Proof 2 (metric). Denote
. Apply the Ceva's theorem to the points
and 
is cyclic
.
Remark. Denote
. Apply an well-known relation

.
P4. Let
, the midpoint
of
,
which satisfy
. The bisector of
meet
at
. Let
. Prove that
.
Proof 1 (metric). Observe that
and
. 
. Thus,
.
Apply the Menelaus' theorem to the transversal
and
.
Proof 2 (synthetic). Prove easily that that
. Denote
for which
. Since
and
obtain that
is the midpoint of
, i.e.
. Notice that the division
is harmonically
, where
is an harmonical division. Since 
is the midpoint of
obtain
, i.e.
. Hence
. Together with
this means that
is an isosceles triangle and
. In conclusion,
.
Lemma. Let
with incenter
and
,
so that
. Then
.
Denote
, the line
so that
and
,
. Suppose w.l.o.g.
and
. Thus,

.[/hide]
P5. Let
be a bisector of
, where
. The line trough the incenters of
and
meets
in
and
in
. Prove that
.
Proof. Is well-known that
. Denote
and apply the upper lemma:

. Since
obtain that
.
P6. Let
and
,
,
be the tangent points of the incircle
with
,
,
respectively.
meets again
at
. Show that
bisects
.
Proof 1. Let
.
Proof 2 (metric).
. Prove easily that

. In conclusion,
.
Lemma. Let
and an interior
for which denote
. Prove that for any
and
so that
exists the relation
.
Remark. In the proof of PP apply the particular cases:
.
P7. Let an acute
with orthocenter
, incenter
and circumcenter
and
. Prove that 
Proof.
. 
. In conclusion,
.
P8. Given
. The bisector of
meets
and circumcircle of
at
,
respectively. Let
,
be midpoints of
,
respectively. The circumcircle of
meets again
at
. The circle passing through
and which is tangent to
at
meets
,
respectively at
,
. Show that
belong to same line.
Proof. Prove easily that
. Thus,
.
Therefore,
. Thus, 
. Since
is cyclically obtain that
. In conclusion,
.
P9. Let
be the
-bisector of
, where
. The incircles of the triangles
, 
touch
at the points
,
respectively. Prove that
.
Proof. I"ll use the relations
and
. Thus,
and 
truly.
P10. Let
with
and
so that
. Prove that
.
Proof. Denote
and apply an well-known identity
. Apply the Menelaus' theorem to the transversals:
.
P11 (Samuel Palacios Paulino). Let
with the incircle
which touches
,
at
,
respectively. Denote the midpoint
of
, the
projection
of
on
, the point
so that
and the intersections
,
. Prove that
.
Proof. Suppose w.l.o.g. that
. Observe that
. The triangles
and
have 
and
. From an well-known property obtain that

Remark 1.

Remark 2. Apply the Menelaus' theorem to
P12 (Samuel Palacios Paulino). Let
with the incircle
which touches
,
at
,
respectively
and
,
so that
and
is the bisector of
. Prove that
.
Proof. Prove easily that
. I"ll use the length
of the
-bisector in the standard
. Therefore,

. With
, i.e.
, the relation
becomes

Remark. Prove similarly that an easy its extension
, where
. Very nice problem!
P13. Let
with orthic
where
,
,
, orthocenter
and
,
so that
and
is the bisector of
. Prove that
.
Proof. Prove easily that
. I"ll use the length
of the
-bisector in the standard
. Therefore,
.
P14..Let
be the circumcircle of
and
be the diameter of
. Consider collinear points
,
,
. Prove that 
Proof. Let
we have
therefore
is cyclic hence
hence
is cyclic. By similarity
of triangles
and
we have :
.Now consider
. Hence
and
.
Hence
, i.e.
is cyclic. Therefore
. Therefore
is cyclic then 
Lemma. For
let incenter
,
-excenter
reflection
of
w.r.t. the circumcenter and second intersection
of
with the circumcircle.
Incircle and
- excircle touch
in
and
respectively. Then the intersections
and
belong to the circumcircle.
Proof. Denote
- the power of the point
w.r.t. the circumcircle
of the triangle
I recall
the well-known relations :
and 
and
, i.e.

and
, i.e.

Observe the "identity" between the two above proofs :
Enunciation. For
denote the incenter
, the
- exincenter and the reflection
of the point
w.r.t. the circumcenter.
Define the intersections :
. Prove that : 
Proof. I"ll use the notations from the above lemma. Apply the Pascal's theorem in the following two pairs of hexagons :

P15. Let an acute
with the orthocenter
and the orthic
, where
,
and
. Prove that 
Denote
. Prove
.
Denote the points
so that
and
. Prove that
.
Proof.
Let
,
be second intersections of
,
respectively with the circumcircle of
. Thus, 
cyclic, i.e.
, i.e.
, i.e.
is cyclic.
.
P16. Let
and
such that
bisects angle
. IF
,
and
, THEN find
and
.
Proof 1.
. Let the common second point
of
with the circumcircle of
. Thus, 

Thus,
, i.e.
. Therefore,
. In conclusion,
.
Proof 2. Exists
so that
. Apply the Stewart's relation

.
Proof 3. Exists
so that
. Apply the generalized theorem of Cosines 
.
Remark. If
and
, then
.
P17. Let
with the incenter
. The circumcircle
of
cut the sidelines
,
in the points
,
respectively. Prove that
.
Proof 1. Suppose w.l.o.g.
, i.e.
and
. Thus, the
-excenter
,
is a diameter of
and 
Apply the power of point
w.r.t. 

Proof 2.
, where
is diameter of
and
is the bisector of
,
and
.
P18. Let an acute
with incircle
and circumcircle
. The circles
and
are tangent internally to
in the same point
.
The circle
is tangent externally to the circle
and is tangent internally to the circle
. Prove that
, where
is the semiperimeter and
is the area for
.
Remark. Prove easily that
. The relations
are well-known.
Proof 1. Denote
. Apply the Stewart's theorem in
for the cevian-rays
and


.
Proof 2. Apply the Pythagoras' theorem in the triangles
Therefore,
, i.e.
, where
is the
- exinradius of
.
Remark. Prove easily that two more interesting relations :
and
,
.
.


![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)




![$[AM]$](http://latex.artofproblemsolving.com/1/f/9/1f9b22599237fb6240a50b5f75e8f6ced1292374.png)

Proof 1 (synthetical). Let




![$[MAB]=[MAC]$](http://latex.artofproblemsolving.com/8/9/d/89d2236039a5f13859756da620347cce793b03c1.png)


and
![$\left\{\begin{array}{c}
[ABL]=[AML]=[ACL]\\\\
\widehat{AEL}\equiv\widehat{AML}\equiv\widehat{AFL}\end{array}\right\|$](http://latex.artofproblemsolving.com/4/9/3/4932939b52b69a1698ba2a8fae0f50bdf778003e.png)





From an well-known property obtain that

![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)

Proof 2. Let


![$[AM]$](http://latex.artofproblemsolving.com/1/f/9/1f9b22599237fb6240a50b5f75e8f6ced1292374.png)


![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)



respectively. We observe that






and


![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)







Remark. Prove easily that











Otherwise.












P2. Let








Proof 1.




Proof 2 (trigonometric). Denote








Extension. Let






Proof.


P3. Let



![$[AB]$](http://latex.artofproblemsolving.com/a/d/a/ada6f54288b7a2cdd299eba0055f8c8d19916b4b.png)
![$[AC]$](http://latex.artofproblemsolving.com/0/9/3/0936990e6625d65357ca51006c08c9fe3e04ba0c.png)






Proof 1 (metric). Denote










Proof 2 (metric). Denote








Remark. Denote







P4. Let


![$[AB]$](http://latex.artofproblemsolving.com/a/d/a/ada6f54288b7a2cdd299eba0055f8c8d19916b4b.png)







Proof 1 (metric). Observe that















Apply the Menelaus' theorem to the transversal






Proof 2 (synthetic). Prove easily that that






![$[ED]$](http://latex.artofproblemsolving.com/9/2/9/929b45305c082cd1e656a5a9897f0df75740e43e.png)





is the midpoint of








Lemma. Let






Denote
















P5. Let










Proof. Is well-known that










P6. Let













Proof 1. Let







Proof 2 (metric).













Lemma. Let







Remark. In the proof of PP apply the particular cases:

P7. Let an acute






Proof.












P8. Given





















Proof. Prove easily that


Therefore,














P9. Let






touch




Proof. I"ll use the relations








P10. Let





Proof. Denote





P11 (Samuel Palacios Paulino). Let







![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)
projection








Proof. Suppose w.l.o.g. that







and





Remark 1.




Remark 2. Apply the Menelaus' theorem to



P12 (Samuel Palacios Paulino). Let






and






Proof. Prove easily that




















Remark. Prove similarly that an easy its extension


P13. Let












Proof. Prove easily that








P14..Let








Proof. Let





of triangles






Hence





Lemma. For








Incircle and

![$[BC]$](http://latex.artofproblemsolving.com/e/a/1/ea1d44f3905940ec53e7eebd2aa5e491eb9e3732.png)




Proof. Denote




the well-known relations :

























Enunciation. For





Define the intersections :


Proof. I"ll use the notations from the above lemma. Apply the Pascal's theorem in the following two pairs of hexagons :



P15. Let an acute















Proof.

















P16. Let









Proof 1.











Thus,




Proof 2. Exists







Proof 3. Exists








Remark. If





P17. Let









Proof 1. Suppose w.l.o.g.





![$[I_aI]$](http://latex.artofproblemsolving.com/2/3/0/2300ecd105ea61e6ca96618a1295a7c71c89bbae.png)








Proof 2.

![$[I_aI]$](http://latex.artofproblemsolving.com/2/3/0/2300ecd105ea61e6ca96618a1295a7c71c89bbae.png)






P18. Let an acute







The circle





![$ S=[ABC]$](http://latex.artofproblemsolving.com/a/c/5/ac5489c655a5d312c5c91c4f77c55eadde984421.png)

Remark. Prove easily that


Proof 1. Denote



















Proof 2. Apply the Pythagoras' theorem in the triangles

Therefore,






Remark. Prove easily that two more interesting relations :



.
This post has been edited 118 times. Last edited by Virgil Nicula, Aug 12, 2017, 8:57 AM